Answer:
0.686 g of ice melts each second.
Solution:
As per the question:
Cross-sectional Area of the Copper Rod, A =
Length of the rod, L = 19.6 cm = 0.196 m
Thermal conductivity of Copper, K =
Conduction of heat from the rod per second is given by:
where
= temperature difference between the two ends of the rod.
Thus
Now,
To calculate the mass, M of the ice melted per sec:
where
= Latent heat of fusion of water = 333 kJ/kg
The weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
To find the answer, we have to know about the pressure.
<h3>How to find the weight of a column of air?</h3>
where; F is the force, here it is equal to the weight of the air column, and A is the area of cross section.
Thus, we can conclude that, the weight of a column of air with cross-sectional area 4. 5 m^2 extending from earth's surface to the top of the atmosphere is, 4.56*10^5N.
Learn more about the pressure here:
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<h2>The pressure will become double </h2>
Explanation:
The gas pressure is directly proportional to the mean root square velocity of the constituent molecules of gas .
P ∝ I
Here C₁ , C₂ ------------ Cₙ is the velocities of molecules .
By making these velocities double
The pressure P₀ ∝ 2 II
By dividing II by I
P₀ = 2 P
Thus pressure will become double than its previous value