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elena55 [62]
3 years ago
6

A bag contains 40 cards numbered 1 through 40 that are either red or blue. A card is drawn at random and placed back in the bag.

This is done four times. Two red cards are drawn, numbered 31 and 19, and two blue cards are drawn, numbered 22 and 7. Your friend concludes that red cards and even numbers must be mutually exclusive.Is your friend correct? Explain.
Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that a bag contains 40 cards numbered 1 through 40 that are either red or blue. A card is drawn at random and placed back in the bag.

This is done four times. Two red cards are drawn, numbered 31 and 19, and two blue cards are drawn, numbered 22 and 7.

From the above we cannot conclude that red cards and even numbers are mutually exclusive

Just drawing two red cards and because the two happen to be odd we cannot generalize the red cards have odd numbers.

This might have occurred due to simple chance from a comparatively large number of 40 cards.

Suppose say we have red cards 20, and 19 red 1 blue.

Then drawing 2 from 19 red cards have more probability and this can occur by chance.

So friend's conclusion is wrong.

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Answer:

6 square inches

Step-by-step explanation:

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Which equation is true? Explain your answer.
Liula [17]

Answer:

<h2>12/36</h2>

Step-by-step explanation:

1. Find if all of the fractions are equal to the other fraction next to them.

First, let's go with the denominator of all.

6/8 = 4/3

First of all, we can easily say that this is not right, since the fact that, 6 is less than 8, and 4 is greater than 3. That's just signaling that this can't be the answer.

3/5 = 8/10

10/5=2

8/3=??? (doesn't go into 8)

So, this one is also wrong

12/16 = 36/48

48/16=3

36/12=3

<h2>So hence, the last one or 12/16=36/48 is RIGHT.</h2>

----------------------------------------------------------------------------------------------------------

Thanks!

Answered by: FieryAnswererGT

#learnwithbrainly

Want to thank me? MARK ME BRAINLIEST! I'll get happy, you will get happy! EQUAL!

3 0
2 years ago
Please help need answer now!!
Vesna [10]

Answer: 5/2

Step-by-step explanation:

Using slope formula m = rise/run

7 0
3 years ago
Using the following equation, find the center and radius: x2 −2x + y2 − 6y = 26 (5 points)
Lisa [10]

Answer:

Center: (1,3)

Radius: 6

Step-by-step explanation:

Hi there!

x^2-2x + y^2 - 6y = 26

Typically, the equation of a circle would be in the form (x-h)^2+(y-k)^2=r^2 where (h,k) is the center and r is the radius.

To get the given equation x^2-2x + y^2 - 6y = 26 into this form, we must complete the square for both x and y.

<u>1) Complete the square for x</u>

Let's take a look at this part of the equation:

x^2-2x

To complete the square, we must add to the expression the square of half of 2. That would be 1² = 1:

x^2-2x+1

Great! Now, let's add this to our original equation:

x^2-2x+1+y^2-6y = 26

We cannot randomly add a 1 to just one side, so we must do the same to the right side of the equation:

x^2-2x+1+y^2-6y = 26+1\\x^2-2x+1+y^2-6y = 27

Complete the square:

(x-1)^2+y^2-6y = 27

<u>2) Complete the square for y</u>

Let's take a look at this part of the equation (x-1)^2+y^2-6y = 27:

y^2-6y

To complete the square, we must add to the expression the square of half of 6. That would be 3² = 9:

y^2-6y+9

Great! Now, back to our original equation:

(x-1)^2+y^2-6y+9= 27

Remember to add 9 on the other side as well:

(x-1)^2+y^2-6y+9= 27+9\\(x-1)^2+y^2-6y+9= 36

Complete the square:

(x-1)^2+(y-3)^2= 36

<u>3) Determine the center and the radius</u>

(x-1)^2+(y-3)^2= 36

(x-h)^2+(y-k)^2=r^2

Now, we can see that (1,3) is in the place of (h,k). 36 is also in the place of r², making 6 the radius.

I hope this helps!

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3 years ago
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elena-s [515]
The Answer Is, f(x)=x2
4 0
3 years ago
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