If it is not exposed to sunlight often... then it might not be able to produce sufficient amounts
Answer:
h = 13.06 m
Explanation:
Given:
- Specific gravity of gasoline S.G = 0.739
- Density of water p_w = 997 kg/m^3
- The atmosphere pressure P_o = 101.325 KPa
- The change in height of the liquid is h m
Find:
How high would the level be in a gasoline barometer at normal atmospheric pressure?
Solution:
- When we consider a barometer setup. We dip the open mouth of an inverted test tube into a pool of fluid. Due to the pressure acting on the free surface of the pool, the fluid starts to rise into the test-tube to a height h.
- The relation with the pressure acting on the free surface and the height to which the fluid travels depends on the density of the fluid and gravitational acceleration as follows:
P = S.G*p_w*g*h
Where, h = P / S.G*p_w*g
- Input the values given:
h = 101.325 KPa / 0.739*9.81*997
h = 13.06 m
- Hence, the gasoline will rise up to the height of 13.06 m under normal atmospheric conditions at sea level.
Answer:
4 Ohms
Explanation:
The challenging part in this circuit is the bridged setup (diamond-shaped arrangement made of the 4 Ohm resistors). In general, this would first need to be transformed using the Wye-Delta transform to be solved, but in this case we can make a valid simplification: since the diamond arrangement is completely symmetrical, the voltage at the top and the bottom tip of the "diamond" will be identical and no current flows through the 4 Ohm bridge, hence, this resistor can be removed without changing the resulting resistance. After this, it is easy to see that the equivalent resistance of the modified "diamond" is just 4 Ohms.
The remaining top parallel branch of the circuit will be 8 Ohms, and the bottom parallel branch is nominally 8 Ohms. The resulting resistance therefore is 4 Ohms.
(The answer is not 2 Ohms!)