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Luda [366]
3 years ago
5

When boating in shallow areas or seagrass beds, you see a mud trail in your wake where your boat has churned up the bottom. If y

ou see this trail, you should:
Physics
1 answer:
cluponka [151]3 years ago
7 0

Answer:

when boating in the shallow area or sea grass beds and the mud trail in our wake we should stop our vessel and try to tilt the motor out through the water.

Explanation:

If we see a trail like, when boating in the shallow area or sea grass beds and the mud trail in our wake we should stop our vessel and try to tilt the motor out through the water. And with the help of a pole (or long rod) we should move our vessel out of the shallow water region. If not with pole we should try to walk out our vessel out of the region. since, the running motor of the vessel will attract more problems like clouded water and grass getting stuck in the motor.

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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the pendulum is take
Juli2301 [7.4K]

To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:

T =2\pi \sqrt{\frac{L}{g}}

Here,

L = Length

g = Acceleration due to gravity

We can realize that 2 \pi is a constant so it is proportional to the square root of its length over its gravity,

T \propto \sqrt{\frac{L}{g}}

Since the body is in constant free fall, that is, a point where gravity tends to be zero:

g \rightarrow 0 \Rightarrow T \rightarrow \infty

The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.

5 0
3 years ago
The cavity within a copper [β = 51 × 10-6 (C°)-1] sphere has a volume of 1.180 × 10-3 m3. Into this cavity is placed 1.100 × 10-
nikdorinn [45]

Answer:

The answer is "60.74^{\circ}".

Explanation:

Cavity and benzene should be extended in equal quantities.

\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to  (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\

\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\

\to \Delta T = \frac{0.072}{0.001185328 }\\\\ \to \Delta T = 60.74^{\circ}\\

5 0
3 years ago
An ant is crawling along a yardstick that is pointed with the 0-inch mark to the east and the 36-inch mark to the west. It start
galina1969 [7]

Answer:

it moves 25 inches.

Explanation:

the east west bit isn't important, ignore it. if an ant starts at 6 then moves to 19 then we need to subtract 19 from 6, that's 13. then it moves to 7. the difference between 19 and 7 is 12. add that to 13 and you get 25. it's important to remember that there is no such thing as negative distance. if it moved, then it counts.

3 0
3 years ago
2O POINTS!!! Easy Question. Will Mark Brainiest
wel

Answer: The Electrostatic force of attraction or repulsion between two charges shows that the Newton's third law applies to electrostatic forces.

Explanation: Consider two Oppositely charged charges separated by distance d.

The electrostatic force exerted by charge 1 on charge 2 is.

By Coulomb's Law :

               F1  = k \frac{Q1 Q2}{d2}.....................................(1)

The electrostatic force exerted by charge 2 on charge 1 is.

              F2  = - k \frac{Q1 Q2}{d2} ................................. (2)

negative sign shows that force are in opposite direction.

 

From Equation 1 and 2

              F1 = - F2

Which implies Newton Third law.

6 0
3 years ago
If the torque required to loosen the nut that is holding a flat tire in a place on a car has a magnitude of 35 N•m what minimum
VashaNatasha [74]

Answer: F = 130 N

Explanation: Solution:

Convert first 27 cm to m.

27 cm  x 0.01 m / 1 cm = 0.27 m

Calculate the torque using T = Fd

Derive to find force F

F = T /d

  = 35 N.m / 0.27 m

  = 130 N

4 0
3 years ago
Read 2 more answers
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