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Luda [366]
2 years ago
5

When boating in shallow areas or seagrass beds, you see a mud trail in your wake where your boat has churned up the bottom. If y

ou see this trail, you should:
Physics
1 answer:
cluponka [151]2 years ago
7 0

Answer:

when boating in the shallow area or sea grass beds and the mud trail in our wake we should stop our vessel and try to tilt the motor out through the water.

Explanation:

If we see a trail like, when boating in the shallow area or sea grass beds and the mud trail in our wake we should stop our vessel and try to tilt the motor out through the water. And with the help of a pole (or long rod) we should move our vessel out of the shallow water region. If not with pole we should try to walk out our vessel out of the region. since, the running motor of the vessel will attract more problems like clouded water and grass getting stuck in the motor.

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Give an example of something that is cyclic and non - cyclic
LiRa [457]
 a clock .. and i guess a non functioning clock ?

7 0
2 years ago
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
kumpel [21]

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

Car B has to travel a distance of D_A and d_a

where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

7 0
3 years ago
A 42.0-kg parachutist is moving straight downward with a speed of 3.85 m/s. (a) If the parachutist comes to rest with constant a
RideAnS [48]

Answer:

-414.96 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2

F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N

The force the ground exerts on the parachutist is -414.96 N

If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase

5 0
3 years ago
As a space shuttle moves through the dilute ionized gas of Earth's ionosphere, the shuttle's potential is typically changed by -
postnew [5]

Answer:

-2.3 × 10^-9 Coulombs(C).

Explanation:

So, we are given the following data or information or parameters that is going to help us to solve the problem effectively and efficiently;

=> " the shuttle's potential is typically changed by -1.4 V during one revolution. "

=> " Assuming the shuttle is a conducting sphere of radius 15 m".

So, in order to estimate the value for the charge we will be making use of the equation below:

Charge, C =( radius × voltage or potential difference) ÷ Coulomb's law constant.

Note that the value of Coulomb's law constant = 9 x 10^9 Nm^2 / C^2.

So, charge = { 15 × (- 1.4)} / 9 x 10^9 Nm^2 / C^2.

= -2.3 × 10^-9 Coulombs(C).

4 0
3 years ago
If the distance between the center of two objects is quadrupled. The gravitational
Juliette [100K]

Answer:

F' = F/16

Explanation:

The gravitational force between masses is given by :

F=G\dfrac{m_1m_2}{r^2}

If the distance between the center of two objects is quadrupled, r' = 4r

New force will be :

F'=G\dfrac{m_1m_2}{r'^2}\\\\F'=G\dfrac{m_1m_2}{(4r)^2}\\\\F'=\dfrac{Gm_1m_2}{16r^2}\\\\F'=\dfrac{1}{16}\times \dfrac{Gm_1m_2}{r^2}\\\\F'=\dfrac{F}{16}

So, the new force will change by a factor of 16.

6 0
3 years ago
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