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AleksandrR [38]
3 years ago
12

How is atomic energy is produced ?​

Physics
2 answers:
horsena [70]3 years ago
5 0
Yes Fission & Fusion
Georgia [21]3 years ago
3 0

Answer:

Fission and Fusion

Explanation:

There are two basic processes: fission and fusion. In both processes, mass is converted to energy according to the famous equation, e=mc2

In fission, heavy fuel (isotopes of uranium, plutonium, thorium, etc.) atoms split, releasing kinetic energy daughter particles and as radiation. In a reactor plant kinetic energy of the daughter particles is converted to thermal energy as the particles are slowed by the fuel matrix or primary coolant. Radiation is absorbed by various components of the reactor and converted to thermal energy. Thermal energy from both sources is then carried out of the reactor core by primary coolant to a turbine where it is converted to electrical energy which is then transmitted to the power grid.

In fusion, light atoms of hydrogen combine to form helium. Energy released from this reaction will be captured and used to generate electricity as well, once we have constructed a fusion reactor large enough to be self-sustaining (i.e. produce as much or more energy from fusion than needed to start the reaction going).

In the case of nuclear weapons, the tremendous energy from the nearly simultaneous fission/fusion reactions is used to create a fireball, intense radiation, and a large shock wave.

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Which means "to study or examine”?
garik1379 [7]
<span>analyze. Analyze means to study or examine something carefully in a methodical way. ... This verb analyze comes from the noun analysis. The noun analysis was in turn borrowed from Greek, from analyein, or "to dissolve."


hope it helps;)
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8 0
3 years ago
Read 2 more answers
How much energy is required to heat 70 g of water at 20°C to boiling
choli [55]

Answer:

Q=23,430J

Explanation:

Hello,

In this case, since we compute the required energy via:

Q=mC\Delta T

Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:

\Delta T=100-20=80\°C

Therefore, the energy turns out:

Q=70g*4.184\frac{J}{g\°C}*80\°C\\ \\Q=23,430J

Best regards.

3 0
3 years ago
A person weighing 645 N climbs up a ladder to a height of 4.55 m what is the increase in gravitational energy
Lemur [1.5K]

Answer: 2934.75 Joules

Explanation:

Potential energy can be defined as energy possessed by an object or body due to its position.

Mathematically, potential energy is given by the formula;

<em>P.E = mgh</em>

Where P.E represents potential energy measured in Joules.

m represents the mass of an object.

g represents acceleration due to gravity measured in meters per second square.

h represents the height measured in meters.

Given the following data;

Weight =645

Height = 4.55

<em>P.E = mgh</em>

But we know that weight = mg = 645N

Substituting into the equation, we have;

<em>P.E = 645 • 4.55</em>

<em>P.E = 2934.75J</em>

Potential energy, P.E = 2934.75 Joules.

3 0
3 years ago
Object with more momentum will take
inn [45]

Answer:

240 kg * m/s

Explanation:

Given

mass (m) = 60 kg

velocity (v) = 4 m/s

Momentum = ?

We know that

Momentum is the product of mass and velocity so

Momentum = m * v

                   = 60 * 4

                   = 240 kg * m/s

Hope it helps :)

3 0
3 years ago
How do you solve this problem?
Katarina [22]

The particle has acceleration vector

\vec a=\left(-2.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)\,\vec\imath+\left(4.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)\,\vec\jmath

We're told that it starts off at the origin, so that its position vector at t=0 is

\vec r_0=\vec0

and that it has an initial velocity of 12 m/s in the positive x direction, or equivalently its initial velocity vector is

\vec v_0=\left(12\,\dfrac{\mathrm m}{\mathrm s}\right)\,\vec\imath

To find the velocity vector for the particle at time t, we integrate the acceleration vector:

\vec v=\vec v_0+\displaystyle\int_0^t\vec a\,\mathrm d\tau

\vec v=\left[12\,\dfrac{\mathrm m}{\mathrm s}+\displaystyle\int_0^t\left(-2.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)\,\mathrm d\tau\right]\,\vec\imath+\left[\displaystyle\int_0^t\left(4.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)\,\mathrm d\tau\right]\,\vec\jmath

\vec v=\left[12\,\dfrac{\mathrm m}{\mathrm s}+\left(-2.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\right]\,\vec\imath+\left(4.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\,\vec\jmath

Then we integrate this to find the position vector at time t:

\vec r=\vec r_0+\displaystyle\int_0^t\vec v\,\mathrm d\tau

\vec r=\left[\displaystyle\int_0^t\left(12\,\dfrac{\mathrm m}{\mathrm s}+\left(-2.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\right)\,\mathrm d\tau\right]\,\vec\imath+\left[\displaystyle\int_0^t\left(4.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\,\mathrm d\tau\right]\,\vec\jmath

\vec r=\left[\left(12\,\dfrac{\mathrm m}{\mathrm s}\right)t+\left(-1.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2\right]\,\vec\imath+\left(2.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2\,\vec\jmath

Solve for the time when the y coordinate is 18 m:

18\,\mathrm m=\left(2.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)t^2\implies t=3.0\,\mathrm s

At this point, the x coordinate is

\left(12\,\dfrac{\mathrm m}{\mathrm s}\right)(3.0\,\mathrm s)+\left(-1.0\,\dfrac{\mathrm m}{\mathrm s^2}\right)(3.0\,\mathrm s)^2=27\,\mathrm m

so the answer is C.

7 0
3 years ago
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