Answer:
The last part on the right side of the diagram
Explanation:
Im on plato and just got it right :)
37° Celsius is equal to 98.6° Fahrenheit
Answer:
Explanation:
The fish is initially at rest and it is also at rest when the spring is fully stretched at the maximum distance.
Change in gravity potential energy = change in spring potential energy
mgh = 1/2kh^2
Assume gravity constant g is 10m/s^2
2.6*10*h = 1/2*200*h^2
100h^2 - 26h = 0
2h(50h - 13) = 0
h = 0 or h = 13/50 = 0.65m
h = 0 is before the spring is stretched
So the maximum distance is 0.65m.
The average thickness of a sheet of the paper is 0.1 mm.
The number of ice blocks that can be stored in the freezer is 80 blocks of ice.
<h3>Average thickness of a sheet of the paper</h3>
The average thickness of a sheet of the paper is calculated as follows;
average thickness = 6 mm/60 sheets = 0.1 mm /sheet
Thus, the average thickness of a sheet of the paper is 0.1 mm.
<h3>Volume of each block of ice</h3>
Volume = 10 cm x 10 cm x 4 cm
Volume = 400 cm³
<h3>Volume of the freezer</h3>
Volume = 40 cm x 40 cm x 20 cm = 32,000 cm³
<h3>Number of ice blocks that can be stored</h3>
n = 32,000 cm³/400 cm³
n = 80 blocks of ice
Thus, the number of ice blocks that can be stored in the freezer is 80 blocks of ice.
Learn more about average thickness here: brainly.com/question/24268651
#SPJ1
Answer:
The value of the correct angle of banking for the road is
°
Explanation:
Given data
Velocity (v) = 60 
Radius = 150 m
The velocity of the car in this case is given by



Put all the values in above formula we get

2.446
°
Therefore the value of the correct angle of banking for the road is
°