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k0ka [10]
3 years ago
11

a car accelerates from 4 meters/second to 16 meter/second in 4 seconds. The cars acceleration is how many meter/seconds.​

Physics
1 answer:
Allushta [10]3 years ago
4 0

Answer:

=3 metre per second ^2

Explanation:

Formula for acceleration is

V-U÷T

In the given information

V=16

U=4

T=4

Acceleration =16-4/4

=3 metre per second ^2

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An object with a mass of 32 kg has an initial energy of 500). At the end of the experimentthe velocity of the object is recorded
Alik [6]

Answer:

 F = 1.68 N

Explanation:

Let's solve this exercise in parts.

Let's use the concept of conservation of the mechanical nerve

initial

    Em₀ = 500 J

The energy is totally kinetic

     Em₀ = K = ½ m v₀²

     v₀ = \sqrt{\frac{2 Em_{o} }{m} }

     v₀ = √ (2 500/32)

     v₀ = 5.59 m / s

now with kinematics we can find a space

      v² = v₀² - 2 a x

the negative sign is because the body is stopping

       a =( \frac{v_{o}^{2} - v^{2}   }{2x} )  

let's calculate

       a = (5.59² - 5.1²) / 2 50  

       a = 0.0524 m / s²

Finally let's use Newton's second law

     F = ma

     F = 32 0.0524

     F = 1.68 N

7 0
3 years ago
What effect does an u balanced force have on an object?
Free_Kalibri [48]
Effect of balanced force'
*net force is zero
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6 0
3 years ago
A+car+accidently+rolls+off+a+cliff.As+it+leaves+the+cliff+it+has+a+horizontal+velocity+of+13+m/s,it+hits+the+ground+60m+from+the
erastovalidia [21]

Answer:

104.6 m

Explanation:

The motion of the car is a projectile motion, consisting of:

- A horizontal motion at constant speed

- A vertical motion at constant acceleration (acceleration of gravity)

We know that:

The initial horizontal velocity of the car is v_x = 13 m/s, and this is constant during the entire motion, as there are no forces in the horizontal direction

d=60 m is the horizontal distance travelled by the car

Therefore, we can find the total time of flight of the car:

t=\frac{d}{v_x}=\frac{60}{13}=4.62 s

Now we analyze the vertical motion, which is a free fall motion, so we can use the suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the vertical displacement (= the height of the cliff)

u = 0 is the initial vertical velocity

t = 4.62 s is the time of flight

a=g=9.8 m/s^2 is the acceleration of gravity

Solving for s, we find the height of the cliff:

s=0+\frac{1}{2}(9.8)(4.62)^2=104.6 m

4 0
4 years ago
Help me with multiplying fractions and mixed numbers
Rainbow [258]
What fractions do you need to multiply into mixed numbers?
4 0
3 years ago
A car travels on a long, straight highway at a constant speed of 30 m/s when it passes a stationary police motorcycle. As the ca
Kruka [31]

Answer:

180 m

Explanation:

Given:

Uniform speed of the car, U = 30 m/s

Uniform acceleration of the motorcycle = 10 m/s²

For the motorcycle to catch up with the car, the distance traveled must be the same.

For the car;

Distance = Speed × Time

        ⇒ d = u × t

             d = 30 × t

             d = 30t               ......(1)

For the motorcycle;

The stationary police motorcycle has initial speed, u = 0

From equation of motion;

             d = ut + \frac{1}{2}at^{2}

but u = 0

             d = \frac{1}{2}at^{2}

             d = \frac{1}{2}10t^{2}

             d = 5t^{2}               .....(2)

Equating equation (1) and (2)

            30t = 5t²

            \frac{t^{2}}{t} = \frac{30}{5}

            t = 6 seconds

Substituting t = 6 s into equation (2)

            d = 5(6)²

            d = 5 × 36

            d = 180 m

The motorcycle must travel 180 m before it catches up to the car

8 0
4 years ago
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