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ioda
3 years ago
6

¿Es posible determinar el valos de las variables que intervienen en los diferentes movimientos en dos dimensiones?

Physics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

oi

Explanation:

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. A 1.00 kg rock is thrown up into the air from ground level at a speed of 8.00 m/s. The ball travels up
Liula [17]

Answer:

p = -8 kg-m/s

Explanation:

Given that,

Initial speed of the rock, u = 8 m/s

Mass of the rock, m = 1 kg

The ball travels up  to a maximum height, then returns to the ground.

We need to find the rock's momentum as it strikes the  ground. Let v be the final speed of the rock. Its final speed is as same as initial speed i.e. 8 m/s but in negative direction. So

p = mv

p = 1 kg × (-8 m/s)

= -8 kg-m/s

So, the rock's momentum as it strikes the  ground is (-8 kg-m/s).

5 0
3 years ago
PLZ HELP What is necessary condition for production of waves?
N76 [4]

Answer:

The length of the rope must be an integral multiple of the wavelength of the wave.

Explanation:

4 0
3 years ago
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A sound wave has a frequency of 265 hz and a wavelength measured at 1.3
pochemuha

Answer:

V = f λ     speed of wave in terms of frequency and wavelength

t = S / V      time for wave to travel a distance S

t = 91.4 m / 344.5 m/s = .265 sec        time to travel 91.4 m

8 0
2 years ago
A stuntwoman is going to attempt a jump across a canyon that is 77 m wide. The ramp on the far side of the canyon is 25 m lower
charle [14.2K]

Answer:

  She will make the jump.

Explanation:

We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

First we will consider horizontal motion of stunt women

   Displacement = 77 m, Initial velocity = 28 cos 15 = 27.05 m/s, acceleration = 0

Substituting

   77= 27.05t+\frac{1}{2} *0*t^2\\ \\ t=77/27.05=2.85 seconds

So she will cover 77 m in 2.85 seconds

 Now considering vertical motion, up direction as positive

    Initial velocity = 28 sin 15 = 7.25 m/s, acceleration =acceleration due to gravity = -9.8 m/s^2, time = 2.85

    Substituting

           s=7.25*2.85-\frac{1}{2}*9.8*2.85^2=20.69-39.80 =-10.11 m

  So at time 2.85 stunt women is 10.11 m below from starting position, far side is 25 m lower. So she will be at higher position.

  So she will make the jump.

6 0
3 years ago
Free point cuz i cewl like dat‍♀️‍♂️
DedPeter [7]
Yes thank u teehee




.................... x
8 0
2 years ago
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