Answer:
Yeah same here
Step-by-step explanation:
1:24 and 2:20 and 3:30 and 4:16 and 5:12
Answer:
<u>This assumes that the question was meant to read:</u>
"A triangle has side lengths of (7x−4) centimeters, (x+3) centimeters, and (<u>3x+2</u>) centimeters." <u>And not </u>"A triangle has side lengths of (7x-4)(7x−4) centimeters, (x+3)(x+3) centimeters, and (3y+2)(3y+2) centimeters."
If the revision is correct, the perimeter is 11x + 1 cm
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<u>If the question was correctly written, then answer is:</u>
50x^2 - 50x + 9y^2 + 12 y + 29
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Step-by-step explanation:
(7x-4) cm
+ (x+3) cm
<u>+ (3x+2) cm</u>
11x + 1 cm
If the question was correctly written as is, then:
(7x-4)(7x−4) = 49x^2 - 56x + 16
+(x+3)(x+3) = + x^2 + 6x + 9
+(3y+2)(3y+2) = <u> +9y^2 + 12 y + 4</u>
50x^2 - 50x + 9y^2 + 12 y + 29 cm
9514 1404 393
Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.
This is same as (4x-6)(2x), so you can distribute 2x into 4x-6 and you would get
(2x)4x - (2x)6 = 8x² - 12x
Final answer: 8x² - 12x
Hope this helps.