URGENT PLEASE HELP!
1 answer:
You might be interested in
Answer:
(a)
(b)
(c)
Explanation:
Hello,
In this case, given the molality in mol/L, we can compute the required units of concentration assuming a 1-L solution of acetonitrile and lithium bromide that has 1.80 moles of lithium bromide:
(a) For the molality, we first compute the grams of lithium bromide in 1.80 moles by using its molar mass:
Next, we compute the mass of the solution:
Then, the mass of the solvent (acetonitrile) in kg:
Finally, the molality:
(b) For the mole fraction, we first compute the moles of solvent (acetonitrile):
Then, the mole fraction of lithium bromide:
(c) Finally, the mass percentage with the previously computed masses:
Regards.