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Tpy6a [65]
3 years ago
5

The characteristic bright–line spectrum of potassium is produced when electrons

Chemistry
1 answer:
OLEGan [10]3 years ago
8 0

Answer: B.

Explanation:

When the electron changes levels, it decreases energy and the atom emits photons. The photon is emitted with the electron moving from a higher energy level to a lower energy level. The energy of the photon is the exact energy that is lost by the electron moving to its lower energy level.

Hope this helps!

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Why does argon exist in nature as individual argon atoms and chlorine exist in nature as 2 chlorine atoms covalently bonded toge
Katarina [22]

Answer:

Argon has 8 valence electrons and no extras, it does not require a bond in order to fill its shells, its satisfied by itself.

Chlorine is missing 1 Electron, if it connects with another Chlorine it will be satisfying both of their needs with a Covalent bond.

Explanation:

8 0
3 years ago
How many grams of barium chloride (BaCl2) are there in 0.187 mol?<br> 0.187 mol
igor_vitrenko [27]

Answer:

38.9 grams of BaCl_2

Explanation:

0.187 mol BaCl2 x \frac{208 g}{1 mol}

0.187 m x 208 g/m

0.187 x 208 g

38.896 g --> 38.9 g BaCl2

8 0
3 years ago
Please help
sergey [27]

Answer:

The scientific method is an empirical method of acquiring knowledge that has characterized the development of science since at least the 17th century.

The basic steps of the scientific method are:

1) investigation

2) hypothesis

3) interpretation

4) conclusions

7 0
3 years ago
What are 3 permeable materials
gizmo_the_mogwai [7]
Permeable materials for what 
4 0
4 years ago
Read 2 more answers
The half-life for the radioactive decay of ce−141 is 32.5 days. if a sample has an activity of 3.8 μci after 162.5 d have elapse
Umnica [9.8K]
Answer : 121.5 <span>μCi

Explanation : We have Ce-141 half life given as 32.5 days so if the activity is 3.8 </span><span>μci after 162.5 days of time elapsed we have to find the initial activity.

We can use this formula;

</span>\frac{N}{ N_{0} } =  e^{-( \frac{0.693 X  T_{2} }{T_{1}})

3.8 / N_{0} = e^ ((0.693 X 162.5 ) / 32.5) = 121.5
<span>
On solving we get, The initial activity as 121.5  </span>μci
5 0
3 years ago
Read 2 more answers
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