Problem: 2x^2+3x-9
For a polynomial of the form, ax^2+bx+c rewrite the middle term as the sum of two terms whose product a·c=2·-9=-18 and whose sum is b=3.
Factor 3 out of 3x
2x^2+3(x)-9
Rewrite 3 as -3 plus 6.
2x^2+(-3+6)x-9
Apply the distributive property
2x^2(-3x+6x)-9
Remove the parentheses
2x^2-3x+6x-9
Factor out the greatest common factor from each group
Group the first two terms and the last two terms
(2x^2-3x) (6x-9)
Factor out the greatest common factor in each group.
x(2x-3)+3(2x-3)
Factor the polynomial by factoring out the greatest common factor, 2x-3
(x+3) (2x-3). So, the quotient is 2x-3
Answer:
-66
Step-by-step explanation:
you have to add 7 to both sides which leaves you with 4x=-264.
Now you divide -264/4 which gets you to x=-66
Answer:
49 percent most likely since 10+3 equals 13 and 8+4 equals 12.
Answer:
it will be B
Step-by-step explanation:
because 1 lb is equal to .75 and the graph shows the exact process of if you were to keep adding .75
Answer:![\left[\begin{array}{ccc}-16&15\\-11&1\\15&-15&\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%2615%5C%5C-11%261%5C%5C15%26-15%26%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
-3A + 2B
=![\left[\begin{array}{ccc}-12&3\\-15&-9\\21&-15\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%263%5C%5C-15%26-9%5C%5C21%26-15%5Cend%7Barray%7D%5Cright%5D)
![+ \left[\begin{array}{ccc}-4&12\\4&10\\-6&0\end{array}\right]](https://tex.z-dn.net/?f=%2B%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%2612%5C%5C4%2610%5C%5C-6%260%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{ccc}-16&15\\-11&1\\15&-15&\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-16%2615%5C%5C-11%261%5C%5C15%26-15%26%5Cend%7Barray%7D%5Cright%5D)
