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Ksenya-84 [330]
4 years ago
7

A rectangular solid has a base that measures 12 feet by 16 feet, and a height of two feet. Its surface area is (blank)

Mathematics
1 answer:
nikdorinn [45]4 years ago
6 0

Answer:

192 feet is your answer .

Step-by-step explanation:

12×16=192 feet base.

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8,264 is divisible by 3? True or false?
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Number\ is\ divisible\ by\ 3\ if\ the\ sum\ of\ the\ digits\ is\ divisible\ by\ 3.\\\\8,264\\\\8+2+6+4=20-
is\ not\ divisible\ by\ 3.\\\\8,264\ is\ divisible\ by\ 3-FALSE
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4 years ago
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Solve the system of equations by substitution. Write your solution as an ordered pair
attashe74 [19]
X + 8x = 81
9x = 81, x = 9
y = 8(9), y = 72
Solution: (9, 72)
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3 years ago
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Mya and ERIC WORK IN A BAKERY . MYA HAS 3 TIMEA AS MUCH FLOUR AS ERIC .MYA HAS 15.81LB OF FLOUR .USE THE EQUATION 3F = 15.81 TO
Pavel [41]

Answer:

5.27 lb

Step-by-step explanation:

Given that,

Mya has 3 times as much floor as Eric. Mya has 15.81 lb of floor. The relation is given by :

Let Eric has F floor.

3F = 15.81 ...(1)

We need to find how much flour Eric has.

Dividing both sides by 15.81.

F = 15.81/3

F = 5.27 lb

Hence, Eric has 5.27 lb of flour.

4 0
3 years ago
Suppose you know the perimeter of n octagons arranged as shown. What would you do to find the perimeter if 1 more octagon was ad
kogti [31]

As shown in the figures given :

For Figure 1 : perimeter = 8 units   [As can be seen in the figure]

For figure 2(with 2 octagons) : perimeter = 8 × 2 - 1 = 15 units    [since 1 side is common ]

For figure 2(with 3 octagons) : perimeter = 8 × 3 - 2 = 22 units  [since 2 sides is common ]

If one more octagon is added

then perimeter = 8 × 4 - 3 = 29 units    [since 3 sides will be common ]


3 0
4 years ago
Given: ∆AMK, MP ⊥ AK , MP = 10 m∠A = 72º, m∠PMK = 50° Find AM, MK, AK
mina [271]

Answer:

Step-by-step explanation:

The diagram of triangle AMK is shown on the attached photo. To determine AM, we would apply trigonometric ratio since triangle AMP is a right angle triangle.

Sin# = opposite/hypotenuse

Sin 72 = 10/AM

AMSin72 = 10

AM = 10/Sin72 = 10/0.9511

AM = 10.51

To determine MK,

Cos# = adjacent/hypotenuse

Cos 50 = 10/MK

MKCos50 = 10

MK = 10/Cos50 = 10/0.6428

MK = 15.6

AK = AP + KP

Tan# = opposite/adjacent

Tan 72 = 10/AP

AP tan 72 = 10

AP =10/tan72 = 10/ 3.0777 = 3.25

Tan 50 = KP/10

KP = 10tan50

KP= 10× 1.1918 = 11.918

Therefore,

AK = 3.25 + 11.918 = 15.168

3 0
3 years ago
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