If the student (which I’m naming student “x”) starts off at running 200m/30secs, then accelerated to 300m/30secs. If it was one minute later, I naturally assume she increases 100m/20secs.
42.9°
Explanation:
Let's assume that the x-axis is aligned with the incline and the positive direction is up the incline. We can then apply Newton's 2nd law as follows:
Note that the net force is zero because the block is moving with a constant speed when the angle of the incline is set at Solving for the angle, we get
or
Answer:
225cos30
Explanation:
Force in the direction of the work done
Use F=ma formula
F=m v/t. a=v/t
put values u will get answer.
answer should be around 30N .
Answer:
The magnitude of the electric field is 5.75 N/C towards positive x- axis.
Explanation:
Given that,
Point charge at origin = 2 nC
Second charge = 5 nC
Distance at x axis = 8 m
We need to calculate the electric field at the point x = 2 m
Using formula of electric field
Put the value into the formula
The direction is toward positive x- axis.
Hence, The magnitude of the electric field is 5.75 N/C towards positive x- axis.