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erastovalidia [21]
3 years ago
13

It takes a truck 3.56 seconds to slow down from 112 km/h to 87.4 km/h. What is its average acceleration?

Physics
1 answer:
Yuliya22 [10]3 years ago
8 0

Answer:

1.92 m/s2

Explanation:

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3. Suppose you take a pendulum with length L and mass m having a period T to a
natta225 [31]

(C)

Explanation:

t = 2\pi \sqrt{ \frac{l}{g} }

If g is only 1/6 on another planet, then

t = 2\pi \sqrt{ \frac{l}{ \frac{g}{6} } } =  2\pi \sqrt{ \frac{6l}{g} }

=  \sqrt{6} \: (2\pi \sqrt{ \frac{l}{g} } ) = 2.4  \times t(on \: earth)

6 0
2 years ago
A spacecraft is flying toward the moon. The moonÍs gravitational pull on the spacecraft will ___________.
kifflom [539]
A. Increase is correct because the statement said the moons gravitational "PULL"
4 0
3 years ago
Read 2 more answers
A 2N and 6N force pull on an object to the right and a 4N force pulls to the left a 0.5kg object. What is the net force on the o
Angelina_Jolie [31]

Explanation:

F net = 2+6-4 ( 2 and 6 N are in same direction so they get added, 4N in opposite direction so it will be subtracted)

F net=4 N

3 0
2 years ago
In a simple machine, the energy input is 120 J. If the efficiency of the machine is 80%, calculate the energy output
pashok25 [27]

Answer:

<h2>96 Joules</h2>

Explanation:

We know that efficiency is the ratio of output power by input power. i.e. Efficiency describes the quality of machine or system how good it is.

Solution,

Energy input of system = 120 J

Efficiency = 80% = \frac{80}{100}  = 0.8

Now,

According to definition,

Efficiency = \frac{output}{input}

Cross multiplication:

output \:  =  \: 0.8 \times 120

Calculate the product

output \:  = 96 \: joules

Hope this helps...

Good luck on your assignment...

4 0
3 years ago
Two blocks a and b ($m_a&gt;m_b$) are pushed for a certain distance along a frictionless surface. how does the magnitude of the
Yuki888 [10]

Answer:

the magnitude of the work done by the two blocks is the same.

Explanation:

The work done by block a on block b is given by:

W_a = F_a d

where Fa is the force exerted by block a on block b, and d is the distance they cover.

The work done by block b on block a is given by:

W_b = F_b d

where Fb is the force exerted by block b on block a, and d is still the distance they cover.

For Newton's third law, the force exerted by block a on block b is equal to the force exerted by block b on block a, therefore

F_a = F_b

and so

W_a=W_b

3 0
3 years ago
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