Answer:
Spring constant, k = 5483.11 N/m
Explanation:
It is given that,
Mass of the organ, m = 2 kg
The natural period of oscillation is, T = 0.12 s
Let k is the spring constant for the spring in the scientist's model. The period of oscillation is given by :



k = 5483.11 N/m
So, the spring constant for the spring in the scientist's model is 5483.11 N/m.
Homie I don’t know either♀️Drop out of schl ig ;-;
Answer:
magnitude of the magnetic field 0.692 T
Explanation:
given data
rectangular dimensions = 2.80 cm by 3.20 cm
angle of 30.0°
produce a flux Ф = 3.10 ×
Wb
solution
we take here rectangular side a and b as a = 2.80 cm and b = 3.20 cm
and here angle between magnitude field and area will be ∅ = 90 - 30
∅ = 60°
and flux is express as
flux Ф =
.................1
and Ф = BA cos∅ ............2
so B =
and we know
A = ab
so
B =
..............3
put here value
B =
solve we get
B = 0.692 T
Https://www.slideshare.net/mobile/jan_parker/life-cycle-of-stars-3196871
the answer to your question!
Given :
A box weighing 12,000 N is parked on a 36° slope.
To Find :
What will be the component of the weight parallel to the plane that balances friction.
Solution :
The component of that will be parallel to the plane to balance friction is :

Therefore, component of force to balance friction is F sin 36° .
Hence, this is the required solution.