Two trains leave the station at the same time, one heading east and the other west. the eastbound train travels at 85 miles per
1 answer:
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Answer:
The time required to send the data from Earth to Moon will be 1.28s while for a two way communication, to send it back to the earth, it will take double time i.e. <em>RTT = 2.56s </em>
Explanation:
Distance between Earth and Moon = 385,000 km = 3.85 x 10⁸m
Speed of data travel = speed of light ≈ 3 x 10⁸m/s
As, v=d/t
t=d/v
t=1.28s
RTT = Double of single way time taken = 2x1.28
<em><u>RTT=2.56s</u></em>
Answer:
a) 13.59 m/s²
b) 67.95 m/s
c) 169.875 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
m = Mass
Force
Acceleration of the jet is 13.59 m/s²
Velocity attained at 5 seconds is 67.95 m/s
Distance traveled in the 5 seconds is 169.875 m
Ball is projected upwards with speed 20 m/s
now using kinematics
here when ball returns back to same position.
total displacement of ball will be zero.
So ball will return to initial position with same speed in opposite direction.