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Charra [1.4K]
3 years ago
8

The frequency of a sound wave in water is 15,000 Hz, and the sound wave travels through water at a speed of 1,500 m/s. What is t

he wavelength?
Physics
1 answer:
motikmotik3 years ago
8 0
I think the answer would be 150 m/s
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A sound wave is an example of an electromagnetic wave in nature?
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No. Sorry. A sound wave is a mechanical wave. There's nothing electromagnetic about it.
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1-¿Que tipo de energía usa en su hogar para el alumbrado , la calefacción y artículos de entretenían, entre otros ? 2-¿ de que m
Harman [31]

Answer:

Explanation:

1.-Energía eléctrica ( electricidad ) proveniente de una fuente AC ( es decir de corriente alterna)

2.-Hay un proveedor de servicios que lleva la energía a las comunidades en general y en particular la lleva hasta mi casa y escuela. Se define como acometida eléctrica, la infraestructura que lleva la energía desde la red de distribución al tablero principal en el abonado. La acometida puede ser aérea o subterránea, y normalmente consta de tres conductores ( de los cuales dos son calibre AWG # 8 ( dos fases ) y uno AWG # 10 ( neutro ). Esta configuración permite tener: 120 y 240 (V) en servicio en la casa y suficiente capacidad para la carga eléctrica de una casa normal

3.-Si, el tipo de corriente. En el caso de una linterna se usan "pilas" o baterías de corriente directa ( que no varia en el tiempo), en la casa la corriente es alterna de 60 ciclos por segundo de frecuencia.

4.-Si el voltaje es menor en una medida importante la ampolleta no alumbra por cuanto si por ejemplo el voltaje nominal ( o de funcionamiento es 120 V y el voltaje suministrado es 50 V ese voltaje será insuficiente para hacer funcionar el circuito). Si el voltaje es mayor dígamos 240 V la ampolleta se quema.

5.-El interruptor nos asegura la maniobra a nuestra voluntad del circuito del cual forma parte. Es decir si tengo un circuito de alumbrado ( 1 bombillo y un interruptor ) ese interruptor me permitirá apagar y encender la luz cuando yo quiera.

Los breaker son "interruptores" son dispositivos de protección para caso de sobrecargas y/o cortocircuitos

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3 years ago
How does the work required to accelerate a particle from 10m/s to 20m/s compare to that required to accelerate it from 20m/s to
Stella [2.4K]

The answer is B. It is the same..... hope this helps!

7 0
3 years ago
9.58 A spring of equilibrium length L1 and spring constant k1 hangs from the ceiling. Mass m1 is suspended from its lower end. T
andrey2020 [161]

Answer:

The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.

See attachment below for full solution

Explanation:

This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.

4 0
4 years ago
Aluminum rivets used in airplane construction are made slightly larger than the rivet holes and cooled by "dry ice" (solid CO2)
poizon [28]

Answer:

\rm 4.554\ m m.

Explanation:

<u>Given:</u>

  • Initial temperature, \rm T_i=23.0\ ^\circ C=23 + 273.15 = 296.15\ K.
  • Final temperature, \rm T_f = -78.0\ ^\circ C = -78+273.15=195.15\ K.
  • Diameter of the hole, \rm d = 4.500\ m = 4.500\times 10^{-3}\ m.
  • Expansion coefficient of the Aluminum, \rm \alpha = 2.4\times 10^{-5}\ K^{-1}.

Let the diameter of the rivet at \rm T_i=23.0\ ^\circ C be \rm d_o, such that,

\rm d_o=d+\Delta d

\rm \Delta d is the elongation in the diameter of the rivet.

We know, The change in the diameter of the rivet is related with the change in temperature as:

\rm \dfrac{\Delta d}{d_o}=\alpha \Delta T.

where, \rm \Delta T is the change in temperature = \rm T_f-T_i=-195.15-296.15=-491.30\ K.

Also, \rm \Delta d=d_o-d.

Using these values,

\rm \dfrac{d_o-d}{d_o}=\alpha \Delta T\\1-\dfrac{d}{d_o}=\alpha \Delta T\\\dfrac{d}{d_o}=1+\alpha \Delta T\\\Rightarrow d_o = \dfrac{d}{1+\alpha \Delta T}\\=\dfrac{4.500\times 10^{-3}}{1+2.4\times10^{-5}\times (-491.30)}\\=4.554\times 10^{-3}\ m.\\=4.554\ m m.

It is the required diameter of the rivet at -78.0\ ^\circ C.

4 0
3 years ago
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