Question

A 2.67 g piece of zinc (density = 7.14 g/mL) is added to a graduated cylinder that contains 12.13 mL H 2 O . What will be the final volume reading on the graduated cylinder, in mL?

Answer 1

Answer:

12.50 mL

Explanation:

From the question given above, the following data were obtained:

Mass of Zinc = 2.67 g

Density of Zinc = 7.14 g/mL

Volume of water = 12.13 mL

Final volume reading =?

Next, we shall determine the density of the piece of zinc. This can be obtained as follow:

Mass of Zinc = 2.67 g

Density of Zinc = 7.14 g/mL

Volume of Zinc =?

Density = mass / volume

7.14 = 2.67 / volume of Zinc

Cross multiply

7.14 × volume of Zinc = 2.67

Divide both side by 7.14

Volume of Zinc = 2.67 / 7.14

Volume of Zinc = 0.37 mL

Finally, we shall determine the final volume reading of the graduated cylinder. This can be obtained as follow:

Volume of water = 12.13 mL

Volume of Zinc = 0.37 mL

Final volume reading =?

Final volume reading = (Volume of water) + (Volume of Zinc)

Final volume reading = 12.13 + 0.37

Final volume reading = 12.50 mL

Thus, the final volume reading of the graduated cylinder is 12.50 mL