Answer:
54.5 mL
Explanation:
Let's consider the following balanced equation.
Na₂CO₃(aq) + 2 HNO₃(aq) → 2 NaNO₃(aq) + CO₂(g) + H₂O(l)
44.2 mL of 0.108 M Na₂CO₃ solution react. The moles of Na₂CO₃ that react are:
0.0442 L × 0.108 mol/L = 4.77 × 10⁻³ mol
The molar ratio of Na₂CO₃ to HNO₃ is 1:2. The moles of HNO₃ that reacted are 2/1 × 4.77 × 10⁻³ mol = 9.54 × 10⁻³ mol
9.54 × 10⁻³ moles of HNO₃ are in a 0.175 M solution. The required volume of HNO₃ is:
9.54 × 10⁻³ mol × (1 L/0.175 mol) × (1000 mL/1 L) = 54.5 mL
i want go with option 2
Answer: Fundamental, Key, vital, crucial
