Answer:
Slope = 
Step-by-step explanation:
(x₁ , y₁) = (-9 , -4) & (x₂ ,y₂) = (-3, -6)
Slope = 
![= \frac{-6-[-4]}{-3-[-9]}\\\\= \frac{-6+4}{-3+9}\\\\= \frac{-2}{6}\\\\= \frac{-1}{3}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B-6-%5B-4%5D%7D%7B-3-%5B-9%5D%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-6%2B4%7D%7B-3%2B9%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-2%7D%7B6%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B-1%7D%7B3%7D)
Answer:
w=-1
Step-by-step explanation:
w-6=-4w-11
5w=-5
w=-1
Answer:
Step-by-step explanation:
f(x)=x+4(x^2+2x-3)=4x^2+9x-12
f'(x)=8x+9
f'(x)=0,gives x=-9/8
f(-5)=-5+4(-5-1)(-5+3)=-5+4*-6*-2=43
f(-9/8)=-9/8+4(-9/8-1)(-9/8+3)
=-9/8+4*-17/8*15/8
=-9/8-255/16
=-273/16=-17 1/16
f(5)=4*5^2+9*5-12=100+45-12=133
absolute maximum=133
absolute minimum=-17 1/16
Factor out the cos<span>θ:
</span>cosθ (2sin<span>θ + sqrt3) = 0
</span>Therefore, the only ways this can happen are if either cosθ = 0 or if (2sin<span>θ + sqrt3) = 0
</span>The first case, cosθ = 0 only at θ <span>= pi/2, 3pi/2.
</span>The second case, <span>(2sin<span>θ + sqrt3) = 0 simplifies to:
</span></span>sin<span>θ = (-sqrt3)/2
</span><span><span>θ = 4pi/3, 5pi/3
</span></span><span><span>Therefore the answer is A.
</span></span>
