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Números que suman 6:
3 + 2 + 1 = 6=> 3^2 + 2^2 + 1^2 = 9 + 4 + 1 = 14
4 + 3 - 1 = 6 => 4^2 + 3^2 + (-1)^2 = 16 + 9 + 1 = 26 => do not use negative numbers, because that will increase the other numbers.
5 + 1 + 0 = 6 => 5^2 + 1 + 0 = 25 + 1 + 0 = 26
4 + 2 + 0 = 4^2 + 2^2 + 0 = 16 + 4 = 20
When you use zero the you increase the sum of the squares.
Then the three numbers that yields the minimum sum of the squares is 1, 2 and 3.
You can start by multiplying the first equation by twelve, by doing this you get whole numbers. This yields:
4x + 3y =12
2x - 3y = -30
As you can see, you have two terms that only differ in sign.
By adding both equations together you get this:
6x=-18 or x=-3
The reason why you can add these equations together is illustrated in the next example:
4=x
5=y
4+5=x+y
Simple no?
Now that you now x you can substitute the value in one of the equations and you get the y value:
4*-3 + 3y =12
-12 + 3y =12
3y= 24
y=8
Answer:
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Step-by-step explanation:
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