To factor a quadratic of the form ax^2+bx+c you need to find two values, j and k, which satisfy two conditions...
jk=ac=12 and j+k=b=8, so j and k must be 2 and 6
Then the factors are just (a+j)(a+k), in this case:
(a+2)(a+6)
So the missing term was 6
Answer:
33.42 divided by 6?
Step-by-step explanation:
X= fancy, y= plain
x+y= 7
28x+ 15y=131
solve by substitution
Answer:
f = 16
Step-by-step explanation:
2 = f/8
Cross Multiplying, we get
f = 16
hope it helps!
Answer:
slope: 3; vertex: (5, -8)
Step-by-step explanation:
Compare the given y+8=3(x−5) to the slope-vertex form y - k = m(x - h). We see that the slope, m, must be 3 and the vertex must be (h, k): (5, -8).
