1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aivan3 [116]
3 years ago
15

Four identical metallic objects carry the following charges 1.82 6.65 4.80 and 9.30 C The objects are brought simultaneously int

o contact so that each touches the others Then they are separated a What is the final charge on each object b How many electrons or protons make up the final charge on each object
Physics
1 answer:
GuDViN [60]3 years ago
7 0

Answer:

a) 5.64 C

b) 3.5*10¹⁹ protons

Explanation:

a)

  • Since the four metallic objects are identical, and total charge must be conserved, this means that after brought simultaneously into contact so that each touches the others, once separated, total charge must be the same than before being brought in contact.
  • But due they are identical, after charges were able to transfer freely between them, the four objects must have the same final charge, i.e. the fourth part of the total charge, as follows:

       Q_{n} = \frac{Q_{tot}}{4} = \frac{22.57C}{4} = 5.64 C  (1)

b)

  • This charge will be divided between n protons, since the charge is positive.
  • Since each proton carries a charge equal to the elementary charge e, which value is 1.6*10⁻¹⁹ C, we can find the number of protons in excess, doing the following calculation:
  • n_{p} =\frac{Q_{n}}{e} = \frac{5.64C}{1.6e-19C} = 3.5 e19 C (2)

You might be interested in
A 4n force is applied to an object with a mass of 2kg what is the accelertion of the object
Pavel [41]

As per Newton's law we know that

F = ma

here we know that

F = 4 N

m = 2 kg

so from this equation we will have

4 = 2 a

a = 4/2 = 2 m/s^2

so the acceleration will be 2 m/s^2


5 0
3 years ago
What would we do if we didn't have solar energy?
Anvisha [2.4K]

We would have to use wind or another source

8 0
3 years ago
Read 2 more answers
A 500N person stands 2.5m from a wall against which a horizontal beam is attached. The beam is 6m long and weighs 200N. A cable
Vinil7 [7]

PART A)

Here by force balance along Y direction

Tsin45  + F_y = 500 + 200

Force balance along X direction

Tcos45 = F_x

now by torque balance

Tsin45 (6) = 500 (2.5) + 200 (3)

T(4.24) = 1250 + 600

T = 436.3 N

PART B)

now from above equations

Tsin45 + F_y = 700

F_y = 391.5 N

F_x = Tcos45 = 308.5 N

now net reaction force of wall is given as

F = \sqrt{F_x^2 + F_y^2}

F = 498.4 N

5 0
3 years ago
The following represents a mass attached to a spring oscillating in simple harmonic motion. X(t) = 4.0 cos(3.0t +0.10) units of
kolbaska11 [484]

Answer:

a) A = 4.0 m , b)   w = 3.0 rad / s , c)  f = 0.477 Hz , d) T = 20.94 s

Explanation:

The equation that describes the oscillatory motion is

          x = A cos (wt + fi)

In the exercise we are told that the expression is

          x = 4.0 cos (3.0 t + 0.10)

let's answer the different questions

a) the amplitude is

         A = 4.0 m

b) the frequency or angular velocity

         w = 3.0 rad / s

c) angular velocity and frequency are related

          w = 2π f

           f = w / 2π

           f = 3 / 2π

           f = 0.477 Hz

d) the period

frequency and period are related

           T = 1 / f

           T = 1 / 0.477

           T = 20.94 s

e) the phase constant

          Ф = 0.10 rad

f) velocity is defined by

          v = dx / dt

         

         v = - A w sin (wt + Ф)

speed is maximum when sine is + -1

         v = A w

          v = 4 3

          v = 12 m / s

g) the angular velocity is

          w² = k / m

          k = m w²

          k = 1.2 3²

          k = 10.8 N / m

h) the total energy of the oscillator is

          Em = ½ k A²

           Em = ½ 10.8 4²

          Em = 43.2 J

i) the potential energy is

           Ke = ½ k x²

for t = 0 x = 4 cos (0 + 0.1)

               x = 3.98 m

j) kinetic energy

           K = ½ m v²

for t = 00.1 ²

    v = A w sin 0.10

    v = 4 3 sin 0.10

    v = 1.98 m / s

3 0
3 years ago
A slanted vector has a magnitude of 41 N and is at an angle of 23 degrees north of east. What are the magnitude and direction of
jenyasd209 [6]

Answer:

The horizontal component is 37.74 N to east

The vertical component is 16.02 N to North

Explanation:

Any slant vector has two components

→ Horizontal component = R cos Ф

→ Vertical component = R sin Ф

→ R is the magnitude of the vector

→ Ф is the direction of the vector with positive part of the horizontal axis

A slanted vector has a magnitude of 41 N and is at an angle of 23

degrees north of east

23° north of east means the angle between the vector and the

east direction is 23° (east is the positive horizontal direction)

That means R is 41 N and Ф is 23°

→ R = 41 N , Ф = 23°

→ The horizontal component = 41 × cos(23) = 37.74 N east

→ The vertical component = 41 × sin(23) = 16.02 N North

<em>The horizontal component is 37.74 N to east</em>

<em>The vertical component is 16.02 N to North</em>

7 0
4 years ago
Other questions:
  • A road with a positive cross slope is highest __________.
    8·1 answer
  • An agent has just listed a power plant. This is an example of what type of real estate?
    7·1 answer
  • What force pulls the truck/ramp down towards the track? Group of answer choices
    9·1 answer
  • Applying the Law of Conservation of Momentum
    13·1 answer
  • A 5-kg object experiences forces as shown in the diagram. Which statement best describes the motion of the object? A) The object
    14·1 answer
  • What it the mass of Jupiter?
    8·2 answers
  • One railroad car rolls towards another. Describe the properties of the first car that determine its momentum and how it would im
    10·1 answer
  • Which electromagnetic wave type has the largest wavelength?
    5·1 answer
  • Put them in order need help plz
    10·2 answers
  • A cyclist covers the first part of her journey
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!