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puteri [66]
3 years ago
8

Ryan swings a pail of water in a vertical circle 1.0 m in radius at a constant speed. If the water is NOT to spill on him:

Physics
1 answer:
nexus9112 [7]3 years ago
3 0

Part 1

If water does not spill at the top point of the circular motion then for the minimum speed condition we can say normal force will be zero at the top position

F_g = ma

mg = m\frac{v^2}{R}

g = \frac{v^2}{R}

v = \sqrt{Rg}

given that

R = 1 m

g = 9.8 m/s^2

now from above equation we have

v = \sqrt{1(9.8)} = 3.13 m/s

Part b)

for minimum value of angular speed we will have

\omega = \frac{v}{R}

\omega = \frac{3.13}{1}

\omega = 3.13 rad/s

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A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. Th
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Answer: 0.0180701 s

Explanation:

Given the following :

Length of string (L) = 10 m

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Weight attached to lower end = 1kN = 1×10^3

Using the relation:

Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

g = acceleration due to gravity = 9.8m/s^2

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A horizontal spring is attached to the wall on one end and to a mass on the other end. The mass can slide freely on a frictionle
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Answer:

a) x=0  %T=0,   b) x= A %T=100%,   c) x=-A %T=50%

Explanation:

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we can write the equation of the oscillation

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When seeing the two equations they are equivalent, so what happens with the angle will also happen with time

We are asked for the percentage of the period at three points: at the maximum elongation and at the point of x = 0, in general the distance is measured from the point of the spring without stretching

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a) for the unstretched spring point x = 0

In general, both distance and time are measured from this point, so the percentage of time is zero.

         % T = 0

b) for x = A

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      cos tea = x / A = -1

therefore the angles tea = π rad

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