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Dimas [21]
4 years ago
11

10 POINT PLS HELP

Physics
1 answer:
Hitman42 [59]4 years ago
5 0

Answer: A heat engine cannot be 100% efficient because, according to the law, energy added as heat is always greater than energy removed as heat.

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If the 15.0 cm string is shorter than the 30.0 cm string.
Margaret [11]

Answer:

option c) 2 is the right answer

7 0
3 years ago
A spaceship, at rest in some inertial frame in space, suddenly needs to accelerate. The ship forcibly expels 103 kg of fuel from
Cerrena [4.2K]

Answer:

V_s = 1.8*10^5m/s

Explanation:

There is no external force applied, therefore there is a moment's preservation throughout the trajectory.

<em>Initial momentum  = Final momentum. </em>

The total mass is equal to

m_T= m_1 +m_2

Where,

m_1 = mass of ship

m_2 = mass of fuell expeled.

As the moment is conserved we have,

0=V_fm_2+V_sm_1

Where,

V_f = Velocity of fuel

V_s =Velocity of Space Ship

Solving and re-arrange to V_swe have,

V_s = \frac{V_f m_2 }{m_1}

V_s = \frac{3/5c}{10^6}

V_s = 3.5*10^{-3}c

Where c is the speed of light.

Therefore the ship be moving with speed

V_s = \frac{3}{5}*10^{-3}*3*10^8m/s

V_s = 1.8*10^5m/s

5 0
3 years ago
A rightward force of 246 N is applied to a 35 N suitcase to accelerate it across the floor. The coefficient of friction between
katrin [286]
(35/g) = mass of 3.57kg. (9.8 for g).
<span> (35 x 0.75) = 26.25N. friction. 
</span><span> (246 - 26.25) = net 219.76N. accelerating force.
</span><span> Aceleration = (f/m) = (219.76/3.57) = 61.56m/sec^2</span>
5 0
3 years ago
A rotating space station is said to create “artificial gravity”—a loosely-defined term used for an acceleration that would be cr
Grace [21]

Answer: 0.313 rad/s

Explanation:

The equation that relates the velocity V and the angular velocity \omega in the uniform circular motion is:

V=\omega.r   (1)

Where r=d/2=100m is the radius of the space station (with a diaeter of 200m) that describes the uniform circular motion.

Isolating \omega from (1):

\omega=\frac{V}{r}  (2)

On the other hand, we are told the “artificial gravity” produced by the cetripetal acceleration a_{c} is 9.8m/s^{2}, and is given by the following equation:

a_{c}=\frac{V^{2}}{r}   (3)

Isolating V:

V=\sqrt{a_{c}.r}   (4)

V=31.3049m/s   (5)

Substitutinng (5) in (2):

\omega=\frac{31.3049m/s}{100m}  (6)

\omega=0.313rad/s This is the angular velocity that would produce an “artificial gravity” of 9 9.8m/s^{2}.

6 0
3 years ago
Can someone help me with this free body diagram problem?
zavuch27 [327]
Lol I just finished this
5 0
3 years ago
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