Answer:
option c) 2 is the right answer
Answer:

Explanation:
There is no external force applied, therefore there is a moment's preservation throughout the trajectory.
<em>Initial momentum = Final momentum. </em>
The total mass is equal to

Where,
mass of ship
mass of fuell expeled.
As the moment is conserved we have,

Where,
Velocity of fuel
Velocity of Space Ship
Solving and re-arrange to
we have,



Where c is the speed of light.
Therefore the ship be moving with speed


(35/g) = mass of 3.57kg. (9.8 for g).
<span> (35 x 0.75) = 26.25N. friction.
</span><span> (246 - 26.25) = net 219.76N. accelerating force.
</span><span> Aceleration = (f/m) = (219.76/3.57) = 61.56m/sec^2</span>
Answer: 0.313 rad/s
Explanation:
The equation that relates the velocity
and the angular velocity
in the uniform circular motion is:
(1)
Where
is the radius of the space station (with a diaeter of 200m) that describes the uniform circular motion.
Isolating
from (1):
(2)
On the other hand, we are told the “artificial gravity” produced by the cetripetal acceleration
is
, and is given by the following equation:
(3)
Isolating
:
(4)
(5)
Substitutinng (5) in (2):
(6)
This is the angular velocity that would produce an “artificial gravity” of 9
.