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solong [7]
3 years ago
13

Given that 0.50 g Al and 5.00 g copper(II) chloride dihydrate are combined with 100.0 ml of water, determine which reactant is t

he limiting reactant and calculate the number of grams of copper metal that can form?
??



Secondly, calculate the molarity of the aluminum chloride in the solution, assuming it all dissolved. Neglect the additional water added to the volume from the copper(II) chloride dihydrate.
Chemistry
1 answer:
MArishka [77]3 years ago
3 0
105.50 grams of total object biomass or matter mixed together which is technically chemistry.
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Which method is used to separate the following mixture (a) water + kerosene​
Ad libitum [116K]

Answer:

The separation of kerosene, oil, and water are immiscible liquids, so they can be separated funnel.

8 0
3 years ago
13. What is the atomic mass of an atom if its mass is approximately equal to the following? 1 a. that of carbon-12 b. 4.5 times
12345 [234]

The atomic mass of an atom if its mass is approximately equal to carbon-12 will be 12 and in case of 4.5 times carbon-12 will be 54

Atomic mass of an element is the average mass of the atoms of an element which are measured in atomic mass unit. Or we can also say that the atomic mass is actually the weighted mass is a weighted average of all of the isotopes of elements, in which the mass of each element is multiplied by the abundance of that particular isotope.

So the atomic mass of an atom if the mass is approximately equal to carbon-12 then the mass of the element will be equal to 12 as the atomic mass of carbon-12  is 12.

where as the atomic mass of an atom if its mass is approximately equal to 4.5 times as much as carbon-12 will be ⇒ 4.5×12= 54

To know more about atomic mass

brainly.com/question/16887530

#SPJ1

6 0
1 year ago
A 3.452 g sample containing an unknown amount of a Ce(IV) salt is dissolved in 250.0-mL of 1 M H2SO4. A 25.00 mL aliquot is anal
SOVA2 [1]

Answer:

1,812 wt%

Explanation:

The reactions for this titration are:

2Ce⁴⁺ + 3I⁻ → 2Ce³⁺ + I₃⁻

I₃⁻ + 2S₂O₃⁻ → 3I⁻ + S₄O₆²⁻

The moles in the end point of S₂O₃⁻ are:

0,01302L×0,03428M Na₂S₂O₃ = 4,463x10⁻⁴ moles of S₂O₃⁻. As 2 moles of S₂O₃⁻ react with 1 mole of I₃⁻, the moles of I₃⁻ are:

4,463x10⁻⁴ moles of S₂O₃⁻×\frac{1molI_{3}^-}{2molS_{2}O_{3}^-} = 2,2315x10⁻⁴ moles of I₃⁻

As 2 moles of Ce⁴⁺ produce 1 mole of I₃⁻, the moles of Ce⁴⁺ are:

2,2315x10⁻⁴ moles of I₃⁻×\frac{2molCe^{4+}}{1molI_{3}^-} = 4,463x10⁻⁴ moles of Ce(IV). These moles are:

4,463x10⁻⁴ moles of Ce(IV)×\frac{140,116g}{1mol} = <em>0,0625 g of Ce(IV)</em>

As the sample has a 3,452g, the weight percent is:

0,0625g of Ce(IV) / 3,452g × 100 = <em>1,812 wt%</em>

I hope it helps!

5 0
3 years ago
A star is observed from two positions of Earth in its orbit, in summer and winter. Which of these is the best method to calculat
Fantom [35]

Answer:

D. Calculate the variations in the potions of the star due to movement of Earth in its orbit

6 0
3 years ago
Determine which reaction has the highest activation energy.
Ymorist [56]

Answer:

A.

Explanation:

4 0
2 years ago
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