Answer:
Q = 6688 J
Explanation:
Given data:
Energy absorbed = ?
Mass of water = 80 g
Initial temperature = 40°C
Final temperature = 60°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
specific heat capacity of water 4.18 j/g.°C
ΔT = 60°C - 40°C
ΔT = 20°C
Q = 80 g ×4.18 j/g.°C × 20°C
Q = 6688 J
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