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Anon25 [30]
3 years ago
8

Why is carbon dioxide a pure substance and not a mixture?

Chemistry
1 answer:
Ede4ka [16]3 years ago
5 0
This is because carbon dioxide comes from many things pure if you added anything to it ( like oxygen, or methane ) then It would not be even close to being carbon dioxide anymore...


I hope that this helps you. :)
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Which describes an example of genetic engineering?
Marizza181 [45]

i think its number 3

4 0
3 years ago
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Compounds like CCl₂F₂ are known as chlorofluorocarbons, or CFCs. These compounds were once widely used as refrigerants but are n
natta225 [31]

Answer: Mass Of CFC that needs to evaporate for the freezing of water = 328.24 g

Explanation: Heat gained by the CFC = Heat lost by water

Heat lost by water = Heat required to take water's temperature to 0°c + Heat required to freeze water at 0°c

Heat required to take water's temperature from 33°c to 0°c = mCΔT

m = 201g, C = 4.18 J/(gK), ΔT = 33

mCΔT = 201 × 4.18 × 33 = 27725.94 J

Heat required to freeze water at 0°c = mL

m = 201g, L = 334 J/g

mL = 201 × 334 = 67134 J

Heat gained by CFC to vaporize = mH = 27725.94 + 67134 = 94859.94 J

H = 289 J/g, m = ?

m × 289 = 94859.9

m = 328.24 g

QED!!

7 0
3 years ago
Write the equilibrium expression for N2 (g) + 3 H2 (g) ↔ 2 NH3 (g) + heat I have no idea where to even start, due to the corona
motikmotik

Answer:

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K_{eq}

K is the constant of a certain reaction when it is in equilibrium

N_2 (g) + 3 H_2 (g)\rightleftharpoons 2 NH_3 (g) + heat

The expression of an equilibrium constant will given as:

K_c=\frac{[NH_3]^2}{[N_2][H_2]^3}

5 0
3 years ago
Không tính toán cụ thể mà lý luận để :
kotykmax [81]

Answer:

c) Tìm những chất có hàm lượng đồng bằng nhau trong 4 chất : CuO, Cu2O, CuS, Cu2S.

Explanation:

3 0
3 years ago
Which ions aren't shown in net ionic reactions, because they are present as both reactants and products of the reaction, so they
Anvisha [2.4K]

Explanation:

This is correct!

Ions that exist in both the reactant and product side of the equation are referred to as spectator ions. Overall, they do not partake in the reaction. If they are present on both sides of the equation, you can cancel them out.

An example is;

Na+(aq) + Cl​−​​(aq) + Ag​+(aq) + NO​3​−​​(aq) → Na​+​​(aq) + NO​3​−​​(aq) + AgCl(s)

The ions; Na+, NO​3​−​​(aq) would be cancelled out to give;

Cl​−​​(aq) + Ag​+(aq)  → AgCl(s)

7 0
2 years ago
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