Hey there!
Just say what color you think the mixture would look like if those elements were combined. Personally I don't know because I don't have context, but if it comes to it just pick a color :)
Good luck, have a good night.
Answer:
1. Removing them to an area of fresh air. This helps to prevents further poisoning by the carbon monoxide and increase the amount of oxygen entering into the body. This will help to reduce the concentration of carbon monoxide binding oxygen
2. Administering pure oxygen goes a long way to enhance ventilation and increase the oxygen saturation to 100%. This will help to overcome the effect of the carbon monoxide and promote more hemoglobin binding
Answer: Very small fragments of solid materials or liquid droplets suspended in air are called particulates. ... For example, solid particulates between roughly 1 and 100 μm in diameter are called dust particles, whereas airborne solids less than 1 μm in diameter are called fumes.
Brainliest would be nice!
Explanation:
Answer:
118 mL
Explanation:
We can easily calculate the final volume of the solution (V₂) by applying the following mathematical expression:
V₁ x C₁ = V₂ x C₂
⇒ V₂ = V₁ x C₁/C₂
Given:
V₁ = 10 mL
C₁ = 0.65 M
C₂ = 0.055 M
We replace the data in the mathematical expression to calculate V₂:
V₂ = V₁ x C₁/C₂ = 10 ml x (0.65 M)/ (0.055 M) = 118.18 mL ≅ 118 mL
Answer:
The limiting reactant is the 6.279 g of
Explanation:
We have to start with the <u>reaction</u> between sodium carbonate () and the Nickel (II) Chloride (), so:
We will have a <u>double replacement reaction</u>. Now we have to <u>balance</u> the reaction, so:
The next step is the <u>calculation of the moles for each reactive</u>. For we have use the <u>molarity equation</u>:
For the calculation of moles of we have to use the <u>molar mass</u> of the compound (129.59 g/mol):
The next step is the division of each mole value by the <u>coefficient of each reactive</u> of the balance reaction. In this case <u>we have "1" for each reactive</u>, so:
The final step is to <u>choose the smallest value</u>. In this case is the value that correspond to . Therefore is the limiting reactive.