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stepan [7]
3 years ago
5

How many grams of N2 are required to produce 100.0 l 0f NH3 at STP?

Chemistry
2 answers:
jarptica [38.1K]3 years ago
7 0
The ideal gas equation is PV = nRT. n = PV/RT n =
(1 atm)(100 L)/(0.08206 L-atm/mol-K)(273K)
 n = 4.46 mol of NH3,we need 2 moles of NH3 to get 1 mole of N2 4.46 mol NH3 so
(1 mol N2/2 mol NH3) = 2.23 moles N2 2.23 moles of N2(28 g N2/1 mol N2) =

Answer is 62.5g N2

Sunny_sXe [5.5K]3 years ago
4 0
It is 62.5g N2--------------
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The gas-phase reaction follows an elementary rate law and is to be carried out first in a PFR and then in a separate experiment
astraxan [27]

Answer:

The activation energy is =8.1\,kcal\,mol^{-1}

Explanation:

The gas phase reaction is as follows.

A \rightarrow B+C

The rate law of the reaction is as follows.

-r_{A}=kC_{A}

The reaction is carried out first in the plug flow reactor with feed as pure reactant.

From the given,

Volume "V" = 10dm^{3}

Temperature "T" = 300 K

Volumetric flow rate of the reaction v_{o}=5dm^{3}s

Conversion of the reaction "X" = 0.8

The rate constant of the reaction can be calculate by the following formua.

V= \frac{v_{0}}{k}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]

Rearrange the formula is as follows.

k= \frac{v_{0}}{V}[(1+\epsilon )ln(\frac{1}{1-X}-\epsilon X)]............(1)

The feed has Pure A, mole fraction of A in feed y_{A_{o}} is 1.

\epsilon =y_{A_{o}}\delta

\delta = change in total number of moles per mole of A reacte.

=1(2-1)=1

Substitute the all given values in equation (1)

k=\frac{5m^{3}/s}{10dm^{3}}[(1+1)ln \frac{1}{1-0.8}-1 \times 0.8] = 1.2s^{-1}

Therefore, the rate constant in case of the plug flow reacor at 300K is1.2s^{-1}

The rate constant in case of the CSTR can be calculated by using the formula.

\frac{V}{v_{0}}= \frac{X(1+\epsilon X)}{k(1-X)}.............(2)

The feed has 50% A and 50%  inerts.

Hence, the mole fraction of A in feed y_{A_{o}} is 0.5

\epsilon =y_{A_{o}}\delta

\delta = change in total number of moles per mole of A reacted.

=0.5(2-1)=0.5

Substitute the all values in formula (2)

\frac{10dm^{3}}{5dm^{3}}=\frac{0.8(1+0.5(0.8))}{k(1-0.8)}=2.8s^{-1}

Therefore, the rate constant in case of CSTR comes out to be 2.8s^{-1}

The activation energy of the reaction can be calculated by using formula

k(T_{2})=k(T_{1})exp[\frac{E}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}})]

In the above reaction rate constant at the two different temperatures.

Rearrange the above formula is as follows.

E= R \times(\frac{T_{1}T_{2}}{T_{1}-T_{2}})ln\frac{k(T_{2})}{k(T_{1})}

Substitute the all values.

=1.987cal/molK(\frac{300K \times320K}{320K \times300K})ln \frac{2.8}{1.2}=8.081 \times10^{3}cal\,mol^{-1}

=8.1\,kcal\,mol^{-1}

Therefore, the activation energy is =8.1\,kcal\,mol^{-1}

8 0
3 years ago
A 5L sample of CO2 at 540 torr and 25 degrees celsius expands to 15L at 32 degrees celsius. What is the pressure of the new cont
saw5 [17]
By  use  of  combined  gas  law
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P1=540  torr
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T2=32+273=305  k

P2  is   therefore=(  305k  x  540 torr  x5 L) /( 15L  x  298)=  184.23  torr
6 0
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Instead of collecting gas with a syringe, another method involves: • Submerging the evidence in a special agent • Placing a stri
kirza4 [7]
Using a tiny vacuum
3 0
2 years ago
What makes thermal imaging cameras useful?
Natali5045456 [20]
Your answer would be C. Thermal is basically an equivalent for temperature . Hope this helps!
6 0
3 years ago
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Calculate the wavelength in nm of ultraviolet light with frequency of 5.5 x 10¹⁵ Hz.
snow_tiger [21]

Answer: Wavelength of ultraviolet light is 54 nm.

Explanation:

Electromagnetic wave is defined as the wave which is associated with both electrical and magnetic component associated with them. They can travel in vacuum as well and travel with the speed of light.

The relationship between wavelength and frequency of the wave follows the equation:

\nu=\frac{c}{\lambda}

where,

\nu = frequency of the wave  =5.5\times 10^{15}Hz

c = speed of light  =3\times 10^8ms^{-1}

\lambda = wavelength of the wave  

Putting in the values we get:

5.5\times 10^{15}s^{-1}=\frac{3\times 10^8ms^{-1}}{\lambda}

\lambda=0.54\times 10^{-7}m

1nm=10^{-9}m

\lambda=54nm

Thus wavelength of ultraviolet light is 54 nm.

6 0
3 years ago
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