M₁=6.584 g
m₂=4,194 g
m(H₂O)=m₁-m₂
w(H₂O)=m(H₂O)/m₁
w(H₂O)=(m₁-m₂)/m₁
w(H₂O)=(6.584-4.194)/6.584=0.3630 (36.30%)
the percentage by mass of water in the hydrate 36.30
Answer:
-10778.95 J heat must be removed in order to form the ice at 15 °C.
Explanation:
Given data:
mass of steam = 25 g
Initial temperature = 118 °C
Final temperature = 15 °C
Heat released = ?
Solution:
Formula:
q = m . c . ΔT
we know that specific heat of water is 4.186 J/g.°C
ΔT = final temperature - initial temperature
ΔT = 15 °C - 118 °C
ΔT = -103 °C
now we will put the values in formula
q = m . c . ΔT
q = 25 g × 4.186 J/g.°C × -103 °C
q = -10778.95 J
so, -10778.95 J heat must be removed in order to form the ice at 15 °C.
Anytime an atom shares or transfers electrons a bond is formed, sharing= covalent and transfer= ionic
C6H12O6 molar mass: 180.15768 g
solute: sugar
molarity = moles of solute / liters of solution
Jones Soda:
33 g / 180.15768 g = 0.18 moles C6H12O6
M = 0.18 g / 0.355 L
M = 0.52
Sierra Mist:
62 g / 180.15768 g = 0.34 moles C6H12O6
M = 0.34 g / 0.591 L
M = 0.58
Sienna Mist has a higher molarity and is more concentrated.
PH is the logarithmic measure of the concentration of hydrogen ions in solution. In an aqueous system, the lowest possible concentration of H+ ions (least acidic) is 1x 10^-14. The -log(1x10^-14) = pH of 14
