How to tell how many solutions a system has khan academy?

(Pls explain I don't really understand the question)

lara [203]

Answer:

When silver nitrate (AgNO3) and potassium chloride (KCl) combine in their liquid state, they form two products by double displacement method.

Silver Chloride (AgCl) and Potassium Nitrate (KNO3)

The reaction is AgNO3 + KCl --- AgCl + KNO3

The precipitate formed is AgCl

Explanation:

6 0

3 years ago

A titration of 0.1 M NaOH into 1.2 L of HCl was stopped once the pH reached 7 (at 25C). If 0.4 L of NaOH needed to be added to a

MArishka [77]

Answer:

0.033 M

Explanation:

Let's consider the neutralization reaction between NaOH and HCl.

NaOH + HCl → NaCl + H₂O

0.4 L of 0.1 M NaOH were used. The reacting moles of NaOH are:

0.4 L × 0.1 mol/L = 0.04 mol

The molar ratio of NaOH to HCl is 1:1. The reacting moles of HCl are 0.04 moles.

0.04 moles of HCl are in 1.2 L. The molarity of HCl is:

M = 0.04 mol / 1.2 L = 0.033 M

4 0

3 years ago

This guy wants to go to the movies with me to watch Avengers Endgame and it's 3 hours long, but he has a girlfriend, and me and

Thepotemich [5.8K]

Answer:

possibly but he could just think of you as a best friend because he has a gf

Explanation:

4 0

4 years ago

Read 2 more answers

Assume that concentrated aqueous NH3 has a density of 0.252 g/mL (0.252 g of NH3 per mL of liquid). Calculate the volume of NH3

Kobotan [32]

The question is incomplete, here is the complete question:

Assume that concentrated aqueous NH₃ has a density of 0.252 g/mL (0.252 g of NH₃ per mL of liquid). Calculate the volume of NH₃ required to contain 0.442 mol?

<u>Answer:</u> The volume of ammonia required is 29.82 mL

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of ammonia = 17 g/mol

Moles of ammonia = 0.442 moles

Putting values in above equation, we get:

$0.442mol=\frac{\text{Mass of ammonia}}{17g/mol}\\\\\text{Mass of ammonia}=(0.442mol\times 17g/mol)=7.514g$

To calculate the volume of ammonia, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Density of ammonia = 0.252 g/mL

Mass of ammonia = 7.514 g

Putting values in above equation, we get:

$0.252g/mL=\frac{7.514g}{\text{Volume of ammonia}}\\\\\text{Volume of ammonia}=\frac{7.514g}{0.252g/mL}=29.82mL$

Hence, the volume of ammonia required is 29.82 mL

4 0

3 years ago

Vapor pressure is ____ related to the temperature of the liquid?

sergiy2304 [10]

Vapor pressure is **directly** related to the temperature of the liquid!! :)

7 0

3 years ago