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tatyana61 [14]
3 years ago
7

Boyle's Law: P1V1=P2V2 The volume of a gas at 99.0 kPa is 300mL. If the pressure increases to 188kPa, what is the final volume?

Chemistry
1 answer:
brilliants [131]3 years ago
6 0

Answer:

158 mL

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 99.0 KPa

Initial volume (V₁) = 300 mL

Final pressure (P₂) = 188 KPa

Final volume (V₂) =?

The final volume of the gas can be obtained by using the Boyle's law equation as illustrated below:

P₁V₁ = P₂V₂

99 × 300 = 188 × V₂

29700 = 188 × V₂

Divide both side by 188

V₂ = 29700 / 188

V₂ = 158 mL

Therefore, the final volume of the gas is 158 mL.

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What information do latitude and longitude provide
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3 0
3 years ago
Cyclopropene decomposes to propene when heated to 500 C, calculate rate constant for the first order reaction 0 min 1.48 mmol/L
Dmitry_Shevchenko [17]

Answer:

k = 0.0306 min-1

Explanation:

The table is given as;

Time, Concentration

0 1.48

5 1.27

10 0.98

15 0.84

The integrated rate law for a first order reaction is given as;

ln [A] = -kt + ln [Ao]

where;

[A] = Final Concentration

[Ao] = Initial Concentration

k = rate constant

t = time

In the table, taking the first two sets of values;

t = 5

k = ?

[Ao]  = 1.48

[A] = 1.27

Inserting into the equation;

ln(1.27) = - k (5) + ln(1.48)

ln(1.27)  - ln(1.48) = -5k

-0.1530 = -5k

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6 0
3 years ago
You have a graduated cylinder with 10 mL of water in it.
Law Incorporation [45]

Answer:

<h3>The answer is 10 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 300 g

volume = final volume of water - initial volume of water

volume = 40 - 10 = 30 mL

We have

density =  \frac{300}{30}  =    \frac{30}{3}  \\

We have the final answer as

<h3>10 g/mL</h3>

Hope this helps you

5 0
3 years ago
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