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2 years ago

You have a graduated cylinder with 10 mL of water in it.

Chemistry

1 answer:

Law Incorporation [45]2 years ago

5 0

Answer:

<h3>The answer is 10 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 300 g

volume = final volume of water - initial volume of water

volume = 40 - 10 = 30 mL

We have

$density = \frac{300}{30} = \frac{30}{3} \\$

We have the final answer as

Hope this helps you

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Physostigmine, an alkaloid obtained from a West African plant (Physotigma venenosum),is used in the treatment of glaucoma. Treat

ozzi

Answer:

The structure of the salt is attached.

Explanation:

Physostigmine, an alkaloid obtained from a West African plant (Physotigma venenosum),is used in the treatment of glaucoma. Treatment of physostigmine with methyl iodide gives a quaternary ammonium salt. What is the structure of this salt?

The structure of the salt is attached

8 0

3 years ago

Number of moles in 37g of magnesium

Ne4ueva [31]

Rounded its 1.522 mol

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3 years ago

Which of these items best describes the arrangement of electrons in an atom of sulfur? A. Eight electrons in its first energy le

Serga [27]

D. Two electrons in its first energy level; eight electrons in its second energy level; six valence electrons in its outermost energy level.

Please correct me if I'm wrong!! :)

6 0

2 years ago

Read 2 more answers

Whenever a continuous bell alarm sounds in the Chemistry building:

deff fn [24]

Answer:

Explanation:

This is essentially one of the several safety measures in the chemical laboratory. This particular approach is one used in the case of fire eventualities.

A is wrong

This is because in the advent of a fire incident, it is necessary to evacuate the building as a whole. Meeting in the hallway is still within the building which is not the right thing to do when there’s a fire outbreak. Occupants are expected to leave the building immediately

B. Is also wrong. Taking time to pack your belongings might make you be caught in the inferno. It is expected that you leave the building at once

4 0

3 years ago

When 7.085 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.71 grams of CO2 and 10.37 grams of H

Taya2010 [7]

Answer:

- Empirical:

$C_3H_7$

- Molecular:

$C_6H_{14}$

Explanation:

Hello,

In this case, based on the information regarding the combustion, the moles of carbon turn out:

$n_C=21.71gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}=0.493molC$

Moreover, the moles of hydrogen:

$n_H=10.37gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH}{1molH_2O}=1.152molH$

Thus, the subscripts of carbon and hydrogen in the hydrocarbon turn out:

$C=\frac{0.4934}{0.4934}=1\\H=\frac{1.15222}{0.4934}=2.335\\CH_{2.335}$

Now, looking for a suitable whole number we obtain the following empirical formula as 2.335 times 3 is 7 for hydrogen:

$C_3H_7$

In such a way, that compound has a molar mass of 43 g/mol, thus, the whole compound's molar mass is 86.18 g/mol for which the molecular formula is twice the empirical one, therefore:

$C_6H_{14}$

Which is hexane.

Best regards.

6 0

3 years ago