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Volgvan
3 years ago
8

What does the law of multiple proportion account for?

Chemistry
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

○ Coefficients in chemical equations

Explanation:

Hope this helps!!!

_liyah

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I have 2 Valence electrons and 1 energy levels
natima [27]

Answer:

Hydrogen(H) and Heluim(He)

Explanation:

These are the only two valennce electrons and 1 energy levels.

3 0
3 years ago
Read 2 more answers
In the Formula 3H2O what is the 3 called
vekshin1

Its very simple .

3H2O ---- three H two O

Its  3 molecules of water

3 0
3 years ago
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I've asked before and gotten spammed hopefully I won't get spammed this time please help me with this someone.​ pls help anyonw
elena55 [62]

Answer:

See below!

Explanation:

A.  The picture of the graph is attached.  You can tell the amount of protons in an element by looking at the periodic table.  The elements are ordered by the number of protons in an element.

B.  Carbon and silicon are at the peaks of the chart.  The peak is the highest point in a graph.

C.  The elements belong to the non-metal group.

D.  The halogens are non-metals, and their vapors are colorless.

The halogens are toxic to humans.

Halogen molecules are made of two atoms; they are diatomic.

Halogens react with non-metals to form crystalline compounds that are salts.

The halogens get less reactive going down the group on the periodic table.

Halogens can bleach vegetable dyes and kill bacteria.

E.  The picture of the table is attached.  To figure which numbers to put where, you need to pay attention to the other numbers.  The halogens follow a trend with each of these properties.  You have to put in the numbers that fit in among the other numbers.

3 0
3 years ago
Consider the following isotopic abundance data for argon (Ar) and silicon (Si):
pshichka [43]

Answer:

Explanation:

Molar mass of Argon

= 35.96755 x .00337 + 37.96272 x .00063 + 39.96240 x .99600

= .12121 + .0239165 + 39.80255

= 39.95

Molar mass of silicon

27.97693 x .9223 + 28.97649 x .0467 + 29.97376 x .0310

= 25.803 + 1.35320 + .929

= 28.08

b )

No of atoms of Si  in 78.2 g = 78.2 x 6.02 x 10²³ / 28.08

= 16.76 x 10²³ .

c )

42 Ar / 40 Ar = 1.05006

42 Ar / 39.95 = 1.05006

42Ar = 41.95

2 )

C₁₆H₁₅F₂N₃O₄S

Mol weight = 16 x 12 + 1 x 15 + 2 x 19 + 3 x 14 + 4 x 16 + 32

= 192 + 15 + 38 + 42 + 64+ 32

= 383

No of molecules = .078 x 6.02 x 10²³ / 383

= 1.226 x 10²⁰ molecules .

7 0
3 years ago
Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow
andreyandreev [35.5K]

Explanation:

(a)  The given data is as follows.

              Pressure on top (P_{o}) = 140 bar = 1.4 \times 10^{7} Pa       (as 1 bar = 10^{5})

              Temperature = 15^{o}C = (15 + 273) K = 288 K

         Density of gas = \frac{PM}{ZRT}

                \frac{dP}{dZ} = \rho \times g

               \frac{dP}{dZ} = \int \frac{PM}{ZRT}

                \int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ

           ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}

                              = 0.4548

                     P_{1} = P_{o} \times e^{0.4548}

                                 = 1.4 \times 10^{7} Pa \times 1.5797

                                 = 2.206 \times 10^{7} Pa

Hence, pressure at the natural gas-oil interface is 2.206 \times 10^{7} Pa.

(b)   At the bottom of the tank,

                 P_{2} = P_{1}  + \rho \times g \times h

                             = 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

                             = 309.8 \times 10^{5} Pa

                             = 309.8 bar

Hence, at the bottom of the well at 15^{o}C pressure is 309.8 bar.

6 0
4 years ago
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