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melomori [17]
3 years ago
9

Which of the following four orbitals is FURTHEST from the nucleus?

Chemistry
1 answer:
coldgirl [10]3 years ago
7 0

Answer:

3P

Explanation:

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What is the volume in L of 3.8 kg of this liquid?
DedPeter [7]
1L ------------ 1 kg
? ------------- 3.8 kg

3.8 x 1 / 1

= 3.8 L
4 0
2 years ago
In a chemical process, three bottles of a standard fluid are emptied into a larger container. A study of the individual bottles
Setler79 [48]

Answer:

a

The expected value is = 39 units

The standard deviation is = 0.1212 unites

b

The probability is = 0.2047 units

Explanation:

The explanation of this answer is shown on the first uploaded image

5 0
3 years ago
Convert 125m^3 to km^3
Ugo [173]

Answer:

1.25e-7

Explanation:

4 0
3 years ago
This is the equation for the combustion of propane.
yan [13]

Answer:

B

Explanation:

Reactants are the compounds which reaction produce the products. In general terms this can be expressed symbolically as follows:

reactants -> products

Other phenomena like heat are omitted because are not always present, that is, only compounds are included. Therefore, in this reaction the reactants are C3H8 (propane) and O2 ( oxygen) and the products are CO2 (carbon dioxide) and H2O (water)

8 0
2 years ago
Read 2 more answers
The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?
Agata [3.3K]

<u>Answer:</u> The molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

<u>Explanation:</u>

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

PbI_2\rightleftharpoons Pb^{2+}+2I^-

                s       2s

The expression for solubility constant for this reaction will be:

K_{sp}=[Pb^{2+}][I^-]^2

We are given:

K_{sp}=7.9\times 10^{-9}

Putting values in above equation, we get:

7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L

Hence, the molar solubility of PbI_2 is 1.25\times 10^{-3}mol/L

3 0
3 years ago
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