5c^5 + 60c^4 + 180c^3
find the GCF, 5c³
5c³(5c^5 + 60c^4 + 180c^3/ 5c^3)
5c³(c² + 12c + 36)
5c³(c² + 2(c)(6) + 6²)
5c³(c + 6)² <<< the answer.
hope this helps, God bless!
If I’m not mistaking it is either 80.29 or 80.30 after rounding,I’m not sure.
The probability of winning a game out of 20 is 4 times.
Answer:
m = 3
n = 14
p = 2
Step-by-step explanation:
Given:

We need to find the values of m, n, p
Solution:
We will first solve the L.H.S
L.H.S = 
Now we will first make the denominator common by taking L.C.M

Now the denominator is common hence we will subtract the numerators.
L.H.S 
Now Comparing the the value of L.H.S with R.H.S we can say that;

m = 3
n = 14
p = 2
Answer:
a=11
Step-by-step explanation:
a=m2 +2
a= (-3)2+2
a=9+2
a=11