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dalvyx [7]
2 years ago
7

Every organism requires a set of instructions that specifies its traits. This information is carried with the cells of the organ

ism. Which set of statements BEST describes hereditary information in eukaryotic cells? Group of answer choices
Biology
1 answer:
Darina [25.2K]2 years ago
7 0

Answer:

This question lacks options, the options are;

A. Genes are made up of chromosomes and both are found in the cell’s cytoplasm.

B. Chromosomes are made up of genes and both are found in the cell’s cytoplasm.

C. Genes are made up of chromosomes and both are found in the cell’s nucleus.

D. Chromosomes are made up of genes and both are found in the cell’s nucleus.

The correct answer is D.

Explanation:

As rightly stated in this question, every living organism requires a set of instructions that specifies its traits. These set of instructions are embedded in a unit called GENE. Genes hold information needed for the survival of a cell in an organism.

These genes are located on a structure called DNA, which are folded or packaged into another structure called CHROMOSOMES. Each chromosome, hence, contains genes that are the unit of inheritance of a cell. In eukaryotic organisms, the gene is found on a chromosome, which is located in the NUCLEUS of the cell.

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Parents and their offspring are usually very similar, but always slightly different. For example, certain moths can have offspri
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Explanation:

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1. Flower position, stem length, and seed shape are three characters that Mendel studied. Each is controlled by an independently
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Answer:

a. 1/64 AATTDD

b. 1/64 aattdd

c. 8/64=1/8 AaTtDd

d. 2/64 = 1/32 AATTDd or aattDd or AAttDd or aaTTDd

Explanation:

<u>Available data:</u>

  • Flower position: Axial (A) is dominant to Terminal (a)
  • Stem length: Tall (T) is dominant to dwarf (t)
  • Seed shape: Round (R) is dominant to wrinkled (r)

<u>Cross</u>:

Parental) AaTtDd   x   AaTtDd

Knowing that these four genes assort independently, then we can infer that the F1 will have the next genotypic proportions for each gene:

  • AA= 1/4

       Aa =2/4

       aa = 1/4

  • TT = 1/4

        Tt = 2/4

         tt = 1/4

  • DD = 1/4

        Dd = 2/4

        dd = 1/4

<em>This is the same as developing a Punnett square for each gene separately.</em>

Knowing this, to get each of the mentioned genotypes for each trait, we must multiply their respective genotypic proportions, like this:

a. homozygous for the three dominant traits, AATTDD

   AA1/4 x TT 1/4 x DD 1/4 = AATTDD 1/64

b. homozygous for the three recessive traits, aattdd

   aa 1/4 x tt 1/4 x dd 1/4 = aattdd 1/64

c. heterozygous for all three characters, AaTtDd

   Aa 2/4 x Tt 2/4 x Dd 2/4 = AaTtDd 8/16=1/8

d. homozygous for axial and tall, heterozygous for seed shape. There are four possibilities, all of them with the same result:

AATTDd --> 1/4  x 1/4 x 2/4 = 2/64=1/32

aattDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

AAttDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

aaTTDd ---> 1/4 x 1/4 x 2/4 = 2/64=1/32

4 0
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Answer:

BB - Dark brown color - (1/4)

Bb - light tan (due to incomplete dominance) - (2/4 or 1/2)

bb - white color - (1/4)

Explanation:

Let the allele for dark brown pigment be represented by "B"

And the let allele for white (no pigment) be represented by "b"

Due to incomplete dominance, the phenotype of heterozygous species would be "light tan"

Genotype of heterozygous female - Bb

Genotype of heterozygous male - Bb

Bb * Bb

BB, Bb, Bb, bb

BB - Dark brown color - (1/4)

Bb - light tan (due to incomplete dominance) - (2/4 or 1/2)

bb - white color - (1/4)

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2 years ago
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