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Vikki [24]
3 years ago
12

Na lost an e- it shrank and the Cl+ grew in size. Does that say anything about the location of the electron before and after it

was transferred
Chemistry
1 answer:
Reptile [31]3 years ago
8 0

Answer:

48

Explanation:

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Answer with explanation and you’ll get brain list
Gwar [14]

Answer:

Option D.

Explanation:

  • 6H₂ + P₄ → 4PH₃

First we convert the given reactant masses into moles, using their respective molar masses:

  • 4.00 g H₂ ÷ 2 g/mol = 2 mol H₂
  • 6.20 g P₄ ÷ 124 g/mol = 0.05 mol P₄

0.05 moles of P₄ would react completely with (6*0.05) 0.3 moles of H₂. There are more H₂ moles than required, meaning H₂ is in excess and P₄ is the limiting reactant.

Now we<u> calculate how many PH₃ moles could be formed</u>, using the <em>number of moles of the limiting reactant</em>:

  • 0.05 mol P₄ * \frac{4molPH_3}{1molP_4} = 0.2 mol PH₃

Finally we <u>convert 0.2 mol PH₃ into grams</u>, using its <em>molar mass</em>:

  • 0.2 mol PH₃ * 34 g/mol = 6.8 g

So the correct answer is option D.

5 0
2 years ago
A buildup of charges in an object is called
8_murik_8 [283]

Answer:

Static Electricity.

Explanation:

Static electricity is defined as 'an electric charge that has built up on an insulated body, often due to friction.' <u> It is an outcome of the disparity among the positive, as well as, negative charges residing in a body</u> or object and causes the charge to build up on the surface of the body. The accumulation of electric charges on the objects like wool, hair, silk, plastic, etc. causes them to possess static electricity. These charges stay on the surface until it is discharged or released through a source. Thus, <u>'static electricity</u>' is the correct answer.

5 0
2 years ago
Cow’s milk is 4.5% by mass of lactose. Calculate the mass of lactose present in 175 g of<br> milk
Reptile [31]

Answer:

7.875 grams

Explanation:

You multiply 175 g by .045

This gives you 7.875 grams of lactose

6 0
3 years ago
675 g of carbon tetrabromide is equivalent to how many
VARVARA [1.3K]
<h3>Answer:</h3>

2.04 mol CBr₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Organic</u>

  • Writing Organic Compounds
  • Writing Covalent Compounds
  • Organic Prefixes

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

675 g CBr₄

<u>Step 2: Identify Conversions</u>

Molar Mass of C - 12.01 g/mol

Molar Mass of Br - 79.90 g/mol

Molar Mass of CBr₄ - 12.01 + 4(79.90) = 331.61 g/mol

<u>Step 3: Convert</u>

<u />\displaystyle 675 \ g \ CBr_4(\frac{1 \ mol \ CBr_4}{331.61 \ g \ CBr_4}) = 2.03552 \ mol \ CBr_4<u />

<u />

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

2.03552 mol CBr₄ ≈ 2.04 mol CBr₄

7 0
3 years ago
Read 2 more answers
What is true about most of the wavelengths found in the electromagnetic spectrum?
olasank [31]
D, you can't see ultraviolet rays and other similar frequency waves with the naked eye.
7 0
2 years ago
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