Answer:
Follows are the answer to this question:
Explanation:
pleas find the attachment file.
Formula for ΔE:

to calculate the value for ΔE put the value in above formula:
Answer:
1281.25 Moles of glucose
Explanation:
Multiply 1.25x1025= 1281.25
Jayne's science teacher mixed a clear liquid with a blue liquid in a beaker. After a few minutes there was a white solid at the bottom of the beaker.So,<span>It is a new substance with different properties.</span>
Triprotic acid is a class of Arrhenius acids that are capable of donating three protons per molecule when dissociating in aqueous solutions. So the chemical reaction as described in the question, at the third equivalence point, can be show as: H3R + 3NaOH ⇒ Na3R + 3H2O, where R is the counter ion of the triprotic acid. Therefore, the ratio between the reacted acid and base at the third equivalence point is 1:3.
The moles of NaOH is 0.106M*0.0352L = 0.003731 mole. So the moles of H3R is 0.003731mole/3=0.001244mole.
The molar mass of the acid can be calculated: 0.307g/0.001244mole=247 g/mol.
Explanation:
The reactions which are not truly of first order but become reactions of first order under certain conditions are called pseudo first order reactions.
For example, hydrolysis of ester