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<span>1 mol mag acetate dissociates into 1 mol Mg ion and 2 mols acetate ions in water. Therefore, if 0.6 mol mg of acetate is dissolved in 0.135 literss of water, we will have 0.6/0.135 = 4.44 moles / lit Mg2+ ions and 0.6*2/0.135 = 8.88 moles / liter C2H3O2- ions.</span>
Answer:
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Explanation:
The concentration of hydroxide ion (-OH) in 1.37 x10^-5 m solution of Ba(OH)2 is calculated as follows
write the equation for dissociation of Ba(OH)2
Ba(OH)2 = Ba^2+(aq) + 2OH^-(aq)
by use of mole ratio between Ba(OH)2 to OH^- which is 1:2 the concentration of OH^- = 2x ( 1.37 x10^-5) = 2.74 x10^-5 M
Answer:
[OH⁻] = 10⁻¹⁴/[H⁺].
Explanation:
∵ [H⁺][OH⁻] = 10⁻¹⁴.
<em>∴ [OH⁻] = 10⁻¹⁴/[H⁺].</em>