Answer:
θ₀ = 84.78° (OR) 5.22°
Explanation:
This situation can be treated as projectile motion. The parameters of this projectile motion are:
R = Range of Projectile = 150 m
V₀ = Launch Speed of Projectile = 90 m/s
g = 9.8 m/s²
θ₀ = Launch angle (OR) Angle of Elevation = ?
The formula for range of a projectile is given as:
R = V₀² Sin 2θ₀/g
Sin 2θ₀ = Rg/V₀²
Sin 2θ₀ = (150 m)(9.8 m/s²)/(90 m/s)²
2θ₀ = Sin⁻¹ (0.18)
θ₀ = 10.45°/2
<u>θ₀ = 5.22°</u>
Also, we know that for the same launch velocity the range will be same for complementary angles. Therefore, another possible value of angle is:
θ₀ = 90° - 5.22°
<u>θ₀ = 84.78°</u>
Answer:
The gravitational force is 130.
Explanation:
During this problem you have to multiply the 65 and the 0.6.
Answer:
Explanation:
<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>
<em>Displacement is the difference in the object's position from one time to another.</em>
<em>Distance is the total amount the object has traveled in a certain period of time.</em>
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<em>I hope this helps!</em>
<em />
The definition of volocity is <span>the speed of something in a given direction.</span>
