B, C, and D are your answers.
Answer:
the work done is zero.
Explanation:
Given;
applied force, F = 8000 N
time of force application, t = 15 s
Work done is given as the product of force and displacement. Since the car is unable to move, then the displacement is zero and the work done is zero.
Work done = Force x displacement
Work done = 8000 N x 0
Work done = 0
Therefore, the work done is zero.
Answer:
reviewing the final statements, the correct one is the quarter
The nail exerts an equal force on the hammer in the opposite direction.
Explanation:
This is an action-reaction problem or Newton's third law, which states that forces in naturals occur in pairs.
This is the foregoing, the hammer exerts a force on the nail of magnitude F and it will direct downwards, if we call this action and the nail exerts a force on the hammer of equal magnitude but opposite direction bone directed upwards, each force is applied in one of the bodies.
The difference in result that each force is that the force between the nail exerts a very high pressure (relation between the force between the nail area), instead the area of the hammer is much greater, therefore the pressure is small.
When reviewing the final statements, the correct one is the quarter
The nail exerts an equal force on the hammer in the opposite direction.
Answer:
233.3N
Explanation:
Given:
radius 'r'= 1.5m
mass 'm'= 165kg
time 't'=2 sec
angular speed 'ω'= 0.6 rev/s
the magnitude of a torque is given by:
τ = F . r = I . α
where, 'α' is the angular acceleration and 'I' is the rotational inertia
F= I . α/ r =>[ ( . m . )(2π . ω/t) ]/r
F=[( . 165 . )(2π . 0.6/2)]/1.5
F= 233.3N
New force is 1/4 of force when distance is doubled