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4 years ago

Since velocity describes both speed and direction you can call it

1 answer:

4 0

Since velocity describes both speed and direction, you can call it a "vector" quantity, and legitimately label it "velocity".

Since speed has no direction, it's a scalar quantity, and it's wrong to call it "velocity" as so many often do.

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What build proteins for cell function in a animal cell

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Ribosome are used for protein synthesis

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4 years ago

Sometimes waves interfere with one another. What type of interference occurs when the crests of one wave and the troughs of anot

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4 years ago

Read 2 more answers

A solar panel is used to recharge a battery. The solar panel produces 0.80 W of electrical power. The panel is 20% efficient. Wh

Vlad [161]

Answer:

Input power, Ip = 4 Watts

Explanation:

Given the following data;

Power output = 0.8 Watts

Efficiency = 20%

To find the power input of the sunlight onto the solar panel;

Mathematically, the efficiency of a machine is given by the formula;

$Efficiency = \frac {Out-put \; power}{In-put \; power} * 100$

Substituting into the formula, we have;

$20 = \frac {0.8}{Ip} * 100$

$20 = \frac {80}{Ip}$

Cross-multiplying, we have;

$20Ip = 80$

$Ip = \frac {80}{20}$

Input power, Ip = 4 Watts

8 0

3 years ago

The development of the cell theory was mostly directly related to the

Mazyrski [523]

Answer:

Development of the gene chromosome theory

Explanation:

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4 years ago

Two capacitors with capacitances of 1.0 m F and 0.50 m F, respectively, are connected in series. The system is connected to a 10

forsale [732]

Answer:

Therefore energy is stored in the 1.0 mF capacitor is 5.56×10⁻⁹ J

Explanation:

Series capacitor: The ending point of a capacitor is the starting point of other capacitor.

If C₁ and C₂ are connected in series then the equivalent capacitance is C.

where $\frac{1}{C} =\frac{1}{C_1}+\frac{1}{C_2}$

Given that,

C₁ = 1.0 mF=1.0×10⁻³F and C₂ = 0.50mF=0.50×10⁻³F

If C is equivalent capacitance.

Then $\frac{1}{C} =\frac{1}{1.0}+\frac{1}{0.5}$

$\Rightarrow \frac{1}{C} =\frac{3}{1}$

$\Rightarrow C=\frac{1}{3}$ mF

Again given that the system is connected to a 100-v battery.

We know that

q=Cv

q= charge

C= capacitor

v= potential difference

Therefore

$q=(\frac{1}{3} \times 10^{-3}\times10) C$

$=\frac{10^{-2}}{3} C$

The electrical potential energy stored in a capacitor can be expressed

$U=\frac{q^2C}{2}$

q= charge

c=capacitance of a capacitor

Therefore energy is stored in the 1.0 mF capacitor is

$U=\frac{q^2C_1}{2}$

$\Rightarrow U=\frac{(\frac{10^{-2}}{3})^2\times 10^{-3} }{2}$

$\Rightarrow U= 5.56\times 10^{-9}$ J

8 0

3 years ago