Question

A boat with a horizontal tow rope pulls a water skier. She skis off to the side, so the rope makes an angle of 12.0 ∘ with the forward direction of motion. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Pushing a stalled car. Part A If the tension in the rope is 200 N, how much work does the rope do on the skier during a forward displacement of 320 m?

Answer 1

Answer:

62.601kJ

Explanation:

We have a force with a horizontal component given by the angle of 15°. So wue can take this component to calculate the total work done, that is,

$W_T = Fd(cos\theta)$

Our values are,

$d=320m$

$Angle = 12\°$

$Force=200N$,

Substituting in Work equation,

$W_T = 200(320)(cos12)$

$W_T = 62601.4J$

$W_T = 62.601kJ$