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Volgvan
3 years ago
5

A boat with a horizontal tow rope pulls a water skier. She skis off to the side, so the rope makes an angle of 12.0 ∘ with the f

orward direction of motion. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Pushing a stalled car. Part A If the tension in the rope is 200 N, how much work does the rope do on the skier during a forward displacement of 320 m?
Physics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

62.601kJ

Explanation:

We have a force with a horizontal component given by the angle of 15°. So wue can take this component to calculate the total work done, that is,

W_T = Fd(cos\theta)

Our values are,

d=320m

Angle = 12\°

Force=200N,

Substituting in Work equation,

W_T = 200(320)(cos12)

W_T = 62601.4J

W_T = 62.601kJ

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Review. From a large distance away, a particle of mass 2.00 g and charge 15.0σC is fired at 21.0 i^ m/s straight toward a second
MissTica

(a)

Determine the system's initial configuration at ri = infinite particle separation and the system's final configuration at the point of closest approach.

Since the two-particle system is not being affected by any outside forces, we may treat it as an isolated system for momentum and use the momentum conservation law.

m1v1 + m1v2 = (m1+m2)v

The second particle's starting velocity is zero, so:

m1v1  = (m1+m2)v

After substituting the values we get,

v = 6i m/s

(b)

Since the two particle system is also energy-isolated, we may use the energy-conservation principle.

dK + dU = 0

Ki +Ui = Kf + Uf

Substituting the values,

1/2m1v1^2i + 1/2 m2v2^2i + 0 = 1/2m1v1^2f + 1/2m2v2^2f +ke q1q2/rf

The second particle's initial speed is 0 (v2 = 0). Additionally, both the first and second particle's final velocity have the same value, v. Put these values in place of the preceding expression:

1/2m1v1^2i  = 1/2m1v1^2 + 1/2m2v2^2 +ke q1q2/rf

After solving we get,

rf = 2ke q1q2 / m1v1^2 - (m1+m2)v^2

Substituting the values we get,

rf = 3.64m

(c)

v1f = (m1-m2 / m1 + m2) v1i

v1f  = -9i m/s

(d)

v2f =  (2m1/ m1 +m2) v1i

After substituting the values,

v2f = 12i m/ s

Question :

Review. From a large distance away, a particle of mass 2.00 g and charge 15.0 \muμC is fired at 21.0 m/s straight toward a second particle, originally stationary but free to move, with mass 5.00 g and charge 8.50 \muμC. Both particles are constrained to move only along the x axis. (a) At the instant of closest approach, both particles will be moving at the same velocity. Find this velocity. (b) Find the distance of closest approach. After the interaction, the particles will move far apart again. At this time, find the velocity of (c) the 2.00-g particle and (d) the 5.00-g particle. \hat{i}

To learn more about  momentum conservation law click on the link below:

brainly.com/question/7538238

#SPJ4

5 0
2 years ago
Can someone answer these questions
Aleks04 [339]

Answer:

1. Following the recoil principle, rockets use combustion (a controlled explosion) to work against earth's gravitational attraction.

2. A force is a push or a pull that acts upon an object as a results of its interaction with another object. ... These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

(via physicsclassroom.com)

3. The combustion throws out material with very high momentum and is, physically speaking, the action. In reaction to that that, the rocket moves away from it (upward when in starts and has the action underneath it)

4. To show the world that commercial manned space missions are safely possible. Some may also like the fact that the US can now do, or rather order, manned flights into space without the help of the russian space agency (Roskosmos).

5. Robert Behnken and Douglas Hurley

6. The international space station (ISS)

7. Yes, Stage 1 of the rocket landed on the drone ship. The crew opened the hatch to enter the space station after 21 hours and 39 minutes after the launch from Cape Canaveral.

8. To have private contractors such as SpaceX actively in the field, there are now more interest groups that participate in space travel. And they can interact with other companies as well.

Also, due to Musks dream and efforts of SpaceX, space travel seems to get a lot cheaper.

That might indeed open the way back to the moon and further to the Mars for human space flight.

Governments such as the US planned on such things for decades, but changed plans ever since, and routinely changed leadership and the opinion on what's important.

Now Spaceflights can become less politically motivated and more commercially. That seems to be a more stable way over long periods of time.

(wrote most of it for you myself, even tough I'm not a native English speaker. would really appreciate the brainliest if you appreciate the work)

5 0
3 years ago
Read 2 more answers
A block-and-tackle pulley hoist is suspended in a warehouse by ropes of lengths 2 m and 3 m. the hoist weighs 430 n. the ropes,
ICE Princess25 [194]
Refer to the diagram shown below.

For horizontal equilibrium,
T₃ cos38 = T₂ cos 50
0.788 T₃ = 0.6428 T₂
T₃ = 0.8157 T₂                (1)

For vertical equilibrium,
T₂ sin 50 + T₃ sin 38 = 430
0.766 T₂ + 0.6157 T₃ = 430
1.2441 T₂ + T₃ = 698.392        (2)

Substitute (1) into (2).
(1.2441 + 0.8157) T₂ = 698.392
T₂ = 339.058 N
T₃ = 0.8157(399.058) = 276.571 N

Answer:
T₂ = 339.06 N
T₃ = 276.57 N

7 0
3 years ago
Engineers can determine properties of a structure that is modeled as a damped spring oscillator, such as a bridge, by applying a
Kazeer [188]

The value of spring constant and the oscillator's damping constant is

K= 6605.667008, b= 0.002884387

Explanation:

For Weakly damping spring oscillator

K/m = W_0^2     (at resonance)

K= mW_0^2

=0.206 * ( 2π * 28.5) ^2

=0.206 * (2π)^2 * (28.5)^2

K= 6605.667008

F = - bV

b= -F/V = -F/ -W_0 * m

=F/W_0 * m

= 0.438N / 2π * 28.5 * 0.848

b= 0.002884387

8 0
3 years ago
A laser emits light at power 6.20 mW and wavelength 633 nm. The laser beam is focused (narrowed) until its diameter matches the
Ipatiy [6.2K]

Answer:

a) S = 1.69 10⁹ W/m², b)  P = 5.63 Pa , c) F = 20.6 10⁻¹² N

Explanation:

a) The intensity defined as the energy per unit area

    S = U / A

Area of ​​a circle is

    W = 6.2 mw = 6.2 10-3 W

    R = 1080 nm = 1080 10⁻⁹ m  = 1.080 10⁻⁶ m

   A = π R2

   A = π (1,080 10⁻⁶)²

   A = 3.66 10 -12 m²

   S = 6.2 10-3 / 3.66 10-12

   S = 1.69 10⁹ W / m²

b) The radiation pressure

   P = 1 / c (dU / dt) / A

   S = (dU / dt) / A

   

   P = S / c

   P = 1.69 10 9 / 3. 108

   P = 5.63 Pa

c) the definition of pressure is force over area

   P = F / A

   F = P A

   F = 5.63 3.66 10⁻¹²

   F = 20.6 10⁻¹² N

d) for this we use Newton's second law

   F = ma

   a = F / m

8 0
3 years ago
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