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Volgvan
3 years ago
5

A boat with a horizontal tow rope pulls a water skier. She skis off to the side, so the rope makes an angle of 12.0 ∘ with the f

orward direction of motion. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Pushing a stalled car. Part A If the tension in the rope is 200 N, how much work does the rope do on the skier during a forward displacement of 320 m?
Physics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

62.601kJ

Explanation:

We have a force with a horizontal component given by the angle of 15°. So wue can take this component to calculate the total work done, that is,

W_T = Fd(cos\theta)

Our values are,

d=320m

Angle = 12\°

Force=200N,

Substituting in Work equation,

W_T = 200(320)(cos12)

W_T = 62601.4J

W_T = 62.601kJ

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Duplain St. is 300 m long and runs from west to east between Baron and Burkey. If Keith is strolling east from Baron at an avera
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Sue from Burkey and Keith from Baron will meet in 2 minutes

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<u>Explanation:</u>

Time taken can be calculated when distance and the speeds are given. Here speeds of Keith and Sue are given. So, we have to find the relative speeds in order to calculate the time taken.

When two objects travel in same direction the relative speed will be the difference between speeds. Similarly when two objects travel in opposite direction, the relative speed will be the sum of given speeds.

Given:

Speed of Sue from Burkey is 6 km/hr and speed of Keith from Baron is 3 km/hr.

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From the formula, d=s \times t

where d is distance,s is speed and t is time

It can be derived that, t=\frac{d}{s}

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