Answer:
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Step-by-step explanation:
We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.
We have to calculate a 95% confidence interval for the proportion.
The sample proportion is p=0.26.
The standard error of the proportion is:
The critical z-value for a 95% confidence interval is z=1.96.
The margin of error (MOE) can be calculated as:

Then, the lower and upper bounds of the confidence interval are:

The 95% confidence interval for the population proportion is (0.192, 0.328).
We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.
Answer:

Step-by-step explanation:

Hope this helps!
Answer:
Based on this information the population in 2019 is <u>23,395</u>. This is because 4.18% of 11,211 is 468.62, times 26(amount of years) is 12,184. After that you would just add the original population(11,211).
Step-by-step explanation:
In order to find the answer, you can use-
1/4x=6
In order to get the answer, you multiply 6 by the denominator.
6x4=24
Then, you'd divide the solution of that part by the numerator.
24 divided by 1 equals 24.
Therefore, the final answer would be 24.
Answer:
19.0, 19.5, 19.054, 19.0541
Step-by-step explanation: