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3 years ago

13

|10+4x|<14 how do you solve this?

2 answers:

Nadya [2.5K]3 years ago

4 0

Answer: - 6 < x < 1

|10 + 4x| < 14

⇔ -14 < 10 + 4x < 14

⇔ -14 - 10 < 4x < 14 - 10

⇔ - 24 < 4x < 4

⇔ -24/4 < x < 4/4

⇔ - 6 < x < 1

Step-by-step explanation:

shutvik [7]3 years ago

3 0

Answer:

-6 < x < 1

Step-by-step explanation:

-14 < 10 + 4x < 14

Subtract 10 from both sides

-24 < 4x < 4

Divide both sides by 4

-6 < x < 1

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Solve x2 + 12x = –11 by completing the square. Which is the solution set of the equation?

Ann [662]

If you would like to solve the equation x^2 + 12 * x = -11, you can calculate this using the following steps:

x^2 + 12 * x = -11
<span>x^2 + 12 * x + 11 = 0
</span>(x + 1) * (x + 11) = 0
1. x = - 1
2. x = - 11

The correct result would be x = - 1, or x = - 11.

7 0

3 years ago

What sum is represented by the following number line?

PilotLPTM [1.2K]

Answer:

B.) 2 3/4 + (-4 1/4) = -1 2/4

Step-by-step explanation:

blue line: forward with positive + $2\frac{3}{4}$

red line: backward with negative - $4\frac{1}{4}$

so the number line follows: $2\frac{3}{4}$ + - $4\frac{1}{4}$ = -1 2/4

4 0

2 years ago

Read 2 more answers

WILL MARK BRAINLIEST <br><br> Which graph represents the solution set of -2y > 7x + 4?

a_sh-v [17]

we have

----> inequality A

The solution of the inequality A is the interval ------> [-1,∞)

-------> inequality B

The solution of the inequality B is the interval ------> (-∞,7]

The solution of the compound inequality is

[-1,∞) ∩ (-∞,7]=[-1,7]

therefore

the answer in the attached figure

8 0

3 years ago

Read 2 more answers

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

3 0

3 years ago

So i need help with this question

lawyer [7]

Answer:

multiply both sides by 8

Step-by-step explanation:

I don't really know why I just know lol hope this helps

8 0

3 years ago