What cell type has no membrane-bound organelles, has DNA that is found in an area called the

State and explain briefly four (4) functions that a machine foundation should fulfill.

MrMuchimi

Answer:

1 The weight of the foundation block should be enough to withstand vibrations

2 The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.

3.The base should be sufficiently rigid to have the requisite rigidity

4 a distance should be created all across machine foundation to separate it from the adjacent parts of the building

Explanation:

1. The weight of the foundation block should be enough to withstand vibrations and to avoid friction between device and the surrounding soil as well. This can be done by increasing the base block weight in supporting with engine power

2.The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.

3.The base should be sufficiently rigid to have the requisite rigidity as the slightest misdirection of foundation may cause significant bearing disorders.

4.To avoid propagation of vibration from a device to the adjacent parts of the building, a distance should be created all across machine foundation to separate it from the adjacent parts of the building.

8 0

4 years ago

A stream of liquid n-pentane flows at a rate of 50.4 L/min into a heating chamber, where it evaporates into a stream of air 15%

allochka39001 [22]

Answer:

(a) the fractional conversion of pentane achieved in the furnace is 90% conversion

(b) the volumetric flow rates (Umin) of the feed air is 256 x 10³ 1/m

(c) the volumetric flow rates (Lmin) of the gas leaving the condenser is 404.9 x 103 l/min

Explanation:

a) Molecular weight of pentane = 72.15 g/mol

density of liquid pentane = 626 kg/m3

Flow rate of feed liquid nitrogen = 50.4 l/min

= 626*50.4*10-3

= 31.55 kg/min

= 31.55/72.15 kmol/min

= 0.4372 kmol/min

Pentane existng the burner = 3.175 kg/min

Fractional conversion = (31.55 - 3.175)/ 31.55

= 0.9 = 90% conversion

b)

C₂H₅ + 8O₂ -----------> 5CO₂ + 6H₂O

From the Stoichiometric reaction,

8 mol of O2 are used for combustion of 1 mol of pentane

for 0.4372 kmol/min of pentane = 8 * 0.4372 kmol/min of Oxygen will be required

= 3.49 kmol/min of O2

amount of air will be = 3.49/0.21 = 16.62 kmol/min

15% excess air = 16.62*1.15 = 19.12 kmol/min

assuming air to be ideal gas

V = nRT / P.........(1)

V = 19.12 X 8.314 X 336 / 208.6

= 256 m³ = 256 x 10³ 1/m

c) Oxygen:

Amount of pentane consumed = (31.55 - 3.175) = 28.375 kg/min = 28.375/72.15 = 0.3932 kmol/min......(2)

Amount of O2 consumed = 8*0.3932 = 3.146 kmol/min

Amount of O2 fed by air = 0.21*19.12 = 4.0215 kmol/mim

unused O2 left = 4.0215 - 3.146

= 0.8755 kmol/min = 19.75*103 l/min............ (using (1))

Carbon Dioxide:

1 mol of pentane = 5 mol of CO2

0.3932 kmol/min of pentane = 5*0.3932 kmol/min of CO2..................(from (2)

= 1.966 kmol/min

= 44.362*103 l/min..........................(using (1))

Nitrogen:

v = 0.79 x 19.12 x 8.314 x 275 / 100.325

= 340.8 m³ / min = 340.8 x 10³ 1/min

Total volumetric flow rate of gases leaving the condenser = (340.8 + 44.36 + 19.75) x 103 l/min

= 404.9 x 103 l/min

6 0

3 years ago

A hypereutectoid steel often presents hard and brittle cementite along the grain boundaries of pearlite. Which of the following

Anvisha [2.4K]

Answer:

(d) Spheroidizing

Explanation:

Spheroidizing

This is the heat treatment process for steel which having carbon percentage more than 0.8 %.As we know that a hard and brittle material is having carbon percentage more than 0.8 %.That is why this process is suitable for the hard materials.

In this process a hard and brittle materials convert into soft and ductile after this it improve the machine ability as well as improve the tool life.

In this process grain become spheroidal and these grains are ductile.

6 0

3 years ago

Given two input integers for an arrowhead and arrow body, print a right-facing arrow. Ex: If the input is 0 1, the output is

Lyrx [107]

For printing a right facing with input 01, define the class for right facing arrow and give the value with appropriate space using '%6d' and then display the right facing arrow.

Further Explanation:

The code to print the arrowhead and arrow body is as follows:

Import java.util.Scanner;

//Define the method.

public class RightfacingArrow

{

//Define the main method.

public static void main(String[] args)

{

//Create an object of Scanner class.

Scanner object = new Scanner(System.in);

//Declare the variables.

int baseChar;

int headChar;

//Prompt the user to enter the input values.

baseChar = object.nextInt();

headChar = object.nextInt();

//Display the headchar in position 6 from the starting.

System.out.printf("%6d ", headChar);

//Display the arrows.

System.out.println(baseChar+""+baseChar+""

+baseChar+""+baseChar+""+baseChar+""

+headChar+""+headChar);

System.out.println(baseChar+""+baseChar

+""+baseChar+""+baseChar+""+baseChar

+""+headChar+""+headChar+""+headChar);

System.out.println(baseChar+""+baseChar

+""+baseChar+""+baseChar+""

+baseChar+""+headChar+""+headChar);

//Display the headchar in position 6 from the starting.

System.out.printf("%6d ", headChar);

}

Output:

If the input is 01, the output will be as below:

1

0000011

00000111

0000011

1

Learn more:

1. A company that allows you to license software monthly to use online is an example of ? brainly.com/question/10410011

2. Prediction accuracy of a neural network depends on _______________ and ______________. brainly.com/question/10599832

Answer details:

Grade: College Engineering

Subject: Computer Science and Enginnering

Chapter: Java Programming

Keyword:

Java, input, output, programming, statements, if-else, loops, print, scan. right facing arrows, body, main body, char, int, variables, scanner class, abstract class, constructor, desctructor

8 0

3 years ago

A production line manufactures 10-liter gasoline cans with a volume tolerance of up to 5%. The probability that any one is out o

melomori [17]

Answer:

In the case of the production Line, we know that,

No of gasoline cans = 5

probability that 1st can is out of tolerance = 0.03

probability that 2nd can is out of tolerance = 0.03

.

probability that the 5th can is out of tolerance = 0.03

Therefore,

probability of 1st can out of tolerance + probability of 1st can not out of tolerance = 1

Probability of 1st can not out of tolerance = 1 -- 0.03 = 0.97

probability of 2nd can not out of tolerance = 0.97

.

probability of 5th can not out of tolerance = 0.97

Question A:

<em>Probability that they are all out of tolerance</em>

= P(1st can out of tolerance) * P(2nd can out of tolerance) * P(3rd can out of tolerance) * P(4th can out of tolerance) * P(5th can out of tolerance)

= (0.03 ) * (0.03) * (0.03) * (0.03) * (0.03) = 2.43 E⁻⁸ (2.43 ˣ 10⁻⁸)

Question B:

<em>Probability that exactly two are out of tolerance</em>

= P(1st can is out of tolerance) * P(2nd can is out of tolerance) * P(3rd can is not out of tolerance) * P(4th can is not out of tolerance) * P(5th can is not out of tolerance)

= (0.03) * (0.03) * (0.97) * (0.97) * (0.97) = 0.0008214057

Explanation:

8 0

3 years ago