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Neporo4naja [7]
3 years ago
9

A hypereutectoid steel often presents hard and brittle cementite along the grain boundaries of pearlite. Which of the following

heat treatments can alleviate this problem by changing the microstructure?(a) Annealing(b) Normalizing(c) Austenizing(d) Spheroidizing(e) Process-annealing
Engineering
1 answer:
Anvisha [2.4K]3 years ago
6 0

Answer:

(d) Spheroidizing

Explanation:

Spheroidizing

 This is the heat treatment process for steel which having carbon percentage more than 0.8 %.As we know that a hard and brittle material is having carbon percentage more than 0.8 %.That is why this process is suitable for the hard materials.

In this process a hard and brittle materials convert into soft and ductile after this it improve the machine ability as well as improve the tool life.

In this process grain become spheroidal and these grains are ductile.

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temperature, T' =  100^{\circ}C

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\rho_{1}v_{i}A_{1} = \rho_{2}v_{e}A_{2}

Now,

\frac{A_{1}v_{i}}{V_{1}} = \frac{A_{2}v_{e}}{V_{2}}

\frac{\frac{\pi d_{i}^{2}}{4}v_{i}}{V_{1}} = \frac{\frac{\pi d_{e}^{2}}{4}v_{e}}{V_{2}}

\frac{\frac{\pi \times 0.08^{2}}{4}\times 3.986}{0.2004} = \frac{\frac{\pi 0.15^{2}}{4}v_{e}}{3.418}

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