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Neporo4naja [7]
3 years ago
9

A hypereutectoid steel often presents hard and brittle cementite along the grain boundaries of pearlite. Which of the following

heat treatments can alleviate this problem by changing the microstructure?(a) Annealing(b) Normalizing(c) Austenizing(d) Spheroidizing(e) Process-annealing
Engineering
1 answer:
Anvisha [2.4K]3 years ago
6 0

Answer:

(d) Spheroidizing

Explanation:

Spheroidizing

 This is the heat treatment process for steel which having carbon percentage more than 0.8 %.As we know that a hard and brittle material is having carbon percentage more than 0.8 %.That is why this process is suitable for the hard materials.

In this process a hard and brittle materials convert into soft and ductile after this it improve the machine ability as well as improve the tool life.

In this process grain become spheroidal and these grains are ductile.

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A program is seeded with 30 faults. During testing, 21 faults are detected, 15 of which are seeded faults and 6 of which are ind
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Answer:

Estimated number of indigenous faults remaining undetected is 6

Explanation:

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A closed, rigid tank is filled with a gas modeled as an ideal gas, initially at 27°C and a gage pressure of 300 kPa. If the gas
ch4aika [34]

Answer:

gauge pressure is 133 kPa

Explanation:

given data

initial temperature T1 = 27°C = 300 K

gauge pressure = 300 kPa = 300 × 10³ Pa

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to find out

final pressure

solution

we know that gauge pressure is = absolute pressure - atmospheric pressure so

P (gauge ) = 300 × 10³ Pa - 1 × 10^{5} Pa

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\frac{P1*V1}{T1} = \frac{P2*V2}{T2}   ................1

so {P2} = \frac{P1*T2}{T1}

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gauge pressure = 1.33 × 10^{5} Pa

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