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vazorg [7]
4 years ago
11

State and explain briefly four (4) functions that a machine foundation should fulfill.

Engineering
1 answer:
MrMuchimi4 years ago
8 0

Answer:

1 The weight of the foundation block should be enough to withstand vibrations

2 The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.

3.The base should be sufficiently rigid to have the requisite rigidity

4 a distance should be created all across  machine foundation to separate it from the adjacent parts of the building

Explanation:

 1. The weight of the foundation block should be enough to withstand vibrations and to avoid friction between device and the surrounding soil as well. This can be done by increasing the base block weight in supporting with engine power

2.The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.

3.The base should be sufficiently rigid to have the requisite rigidity as the slightest misdirection of foundation may cause significant bearing disorders.

4.To avoid propagation of vibration from a device to the adjacent parts of the building, a distance should be created all across  machine foundation to separate it from the adjacent parts of the building. 

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An add tape of 101 ft is incorrectly recorded as 100 ft for a 200-ft distance. What is
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Answer:

the correct distance is 202 ft

Explanation:

The computation of the correct distance is shown below:

But before that correction to be applied should be determined

= (101 ft - 100 ft) ÷ (100 ft) × 200 ft

= 2 ft

Now the correct distance is

= 200 ft +  2 ft

= 202 ft

Hence, the correct distance is 202 ft

The same would be relevant and considered too

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a)

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The answer is computer cookies.

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4 Error-Correcting Polynomials (a) Alice has a length 8 message to Bob. There are 2 communication channels available. When n pac
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(m_{1}, m_{2}, m_{3}) = (3, -6, 3)

<u>Explanation:</u>

Given data,

p=m_{1} x^{2}+m_{2} x+m_{3}

5 packets are delivered by channel, which was randomly taken.

0(P(0)), 1(P(1)), 2(P(2)), 3(P(3)), 4(P(4))

Bob receives are

(0,3) (1,0) (2,3) (3,0) (4,3)

P(0) = 3

P(1) = 0

P(2) = 3

P(3) = 0

P(4) = 3

The given equation is

p=m_{1} x^{2}+m_{2} x+m_{3}

Solution:

p(0)=m_{1}(0)+m_{2}(0)+m_{3} = 3

m_{3} = 3

p(1)=m_{1}+m_{2}+m_{3}=0

m_{1} + m_{2} = - 3

m_{2} = -3 -m_{1}

p(2)=4 m_{1}+2 m_{2}+m_{3} = 3

4 m_{1}+2 m_{2} = 0

2 m_{1}+m_{2}=0

P(3)=9 m_{1}+3 m_{2}+m_{3}  = 0

3 m_{1}+m_{2}+3=0

P(4)=16 m_{1}+4 m_{2}+m_{3} = 3

4 m_{1}+m_{2} = 0

From P(1) and P(2)

m_{2} = -3 -m_{1}

2 m_{1}+m_{2}=0

2 m_{1}-3-m_{1}=0

-3 + m_{1}  = 0

m_{1} = 3

m_{2} = -6

(m_{1}, m_{2}, m_{3}) = (3, -6, 3)

7 0
3 years ago
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