A model rocket consists of a cone on top of a cylinder.

The volume of a cylinder is 400x cm. The radius of the base of the cylinder is 4 cm. What is the height of the cylinder

irina1246 [14]

Answer: 8cm

Step-by-step explanation:

$V=\pi r^2h$

Solve for h;

$h=\frac{V}{\pi r^2}$

$h=\frac{400cm^3}{(3.14)(4cm)^2}$

$h=7.96\\h=8$

3 0

2 years ago

Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?

bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function $f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}$

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for $x=-6$ in the function and simplify the function.

Hence, let us substitute $x=-6$ in the function, we get,

$f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}$

Let us apply the rule $-\left(-a\right)=a$ , we get,

$f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}$

Multiplying the numbers, we get,

$f(-6)=\frac{100}{-10+e^{0.6}}$

The value of $e^{0.6}=1.822$

Substituting the value of $e^{0.6}=1.822$ , we get,

$f(-6)=\frac{100}{-10+1.822}$

Subtracting the denominator, we have,

$f(-6)=\frac{100}{-8.178}$

Dividing, we have,

$f(-6)=-12.228$

Rounding off to the nearest tenth, we have,

$f(-6)=-12.2$

Thus, the value of f(-6) is -12.2

4 0

2 years ago

Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv

Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Ivan has a summer babysitting job that pays $15 per hour. He wants to know how many hours he has to babysit to afford a new bike

exis [7]

Answer: 20 hours

Step-by-step explanation:

Equation: 15x = 300

Isolate the variable.

Divide both sides by 15: ¹⁵ˣ⁄₁₅ = ³⁰⁰⁄₁₅

x = 20

Ivan needs to work 20 hours in order to afford the bicycle.

8 0

2 years ago

Line segments AD and BE intersect at C, and triangles ABC and DEC are formed. They have the following characteristics: ∠ACB and

xenn [34]

Answer: The answer is ASA, ed2020

Step-by-step explanation:

8 0

2 years ago