All categories

3 years ago

Jk =5x+17,KL = x -1,JL=7x-9 find a range of possible values for x

Mathematics

1 answer:

nadya68 [22]3 years ago

3 0

Answer:

x = 25

Step-by-step explanation:

It is given that,

JK =5x+17,

KL = x -1,

JL=7x-9

We need to find the range of possible values for x.

It can be assumed that K is a mid point of JL.

JL = JK + KL

Putting all the values,

7x-9 = 5x+17 + x -1

Taking like terms together,

7x-5x-x = 17-1+9

x = 25

So, the value of x is 25.

You might be interested in

6.8 + [(0.5 times 7) + (3.1 times 3)] answer

andrezito [222]

Answer:

19.6

Step-by-step explanation:

3 0

3 years ago

The square root of the quantity 4 x minus 3 end quantity equals 5.

zavuch27 [327]

Answer:

The statement is false.

Step-by-step explanation:

Given,

$\sqrt{4 \times - 3} = 5$

To Prove

Soln:

$\sqrt{4 \times - 3}$

= $2i \sqrt{3}$

=> $2i \sqrt{3} ≠5$

Hence, 2i√3 is not equal (≠) to 5.

3 0

2 years ago

HELP!

igomit [66]

Answer:

Step-by-step explanation:

6 0

3 years ago

three ounces of cinnamon cost $2.40. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound?

tatiyna

Answer:
One pound equals $38.4
Step-by-step explanation:
Times the ounces by the cost

7 0

2 years ago

Read 2 more answers

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval?

timama [110]

The Mean Value Theorem:
If a function is continuous on [ a, b ] and differentiable on ( a , b ) than there is a point c in ( a, b ) such that:
f ` ( c )= ( f ( b ) - f ( a ) ) / ( b - a )
f ` ( c ) = ( f ( 2 ) - f ( 0 ) ) / ( 2 - 0 )
f `( x ) = 10 x - 3
f ` ( c ) = 10 c - 3
2 f ` ( c ) = 16 - 2
f ` ( c ) = 7
7 = 10 c - 3
c = 1
Answer:
Yes, the function is continuous on [ 0, 2 ] and differentiable on ( 0, 2 ).

4 0

3 years ago